Answer:
- arc BF = 76°
- ∠M = 31°
- ∠BGE = 121°
- ∠MFB = 111°
Step-by-step explanation:
(a) ∠FBM is the complement of ∠FBC, so is ...
∠FBM = 90° -52° = 38°
The measure of arc BF is twice this angle, so is ...
arc BF = 2∠FBM = 2(38°)
arc BF = 76°
__
(b) ∠M is half the difference between the measures of arcs BE and BF, so is ...
∠M = (1/2)(138° -76°) = 62°/2
∠M = 31°
__
(c) arc FC is the supplement to arc BF, so has measure ...
arc FC = 180° -arc BF = 180° -76° = 104°
∠BGE is half the sum of arcs BE and FC, so is ...
∠BGE = (1/2)(arc BE +arc FC) = (138° +104°)/2
∠BGE = 121°
__
(d) ∠MFB is the remaining angle in ∆MFB, so has measure ...
∠MFB = 180° -∠M -∠FBM = 180° -31° -38°
∠MFB = 111°
Answer: 7:35 a. M
Step-by-step explanation:
Given that:
Snooze on alarm = 5 minutes
Snooze on cellphone = 7 minutes
If both activates at 7:00 a. M
Time at which both will activate again ;
Obtain the Lowest Common Multiple of 5 and 7
_5 __|5 ___|7
_7__ |1 ___|7
____ |1 ___| 1
Lowest common multiple = (5 * 7) = 35
Hence, both alarms will sound together again after 35 minutes = 7:00a.m + 35 minutes = 7:35 A. M
We have measures of all tree sides of the both triangles,
so we can use SSS to check if the triangles are similar.
|ED|/|AB| =5/10=1/2
|DC|/|BC| = 4/8 = 1/2
|EC|/|AC| = 6/12 = 1/2
We see that all tree pairs are in proportion, so these triangles ΔABC and ΔEDC are similar.
We have enough information to prove that ΔABC similar to ΔEDC.
Answer:
= 2
Step-by-step explanation:
Since √4 = 2, so
2
Answer:
The probability that a random sample of 10 second grade students from the city results in a mean reading rate of more than 96 words per minute
P(x⁻>96) =0.0359
Step-by-step explanation:
<em>Explanation</em>:-
<em>Given sample size 'n' =10</em>
<em>mean of the Population = 90 words per minute</em>
<em>standard deviation of the Population =10 wpm </em>
<em>we will use formula</em>
<em> </em>
<em></em>
<em>Let X⁻ = 96</em>
Z = 1.898
<em>The probability that a random sample of 10 second grade students from the city results in a mean reading rate of more than 96 words per minute</em>
<em></em>
<em></em>
<em> = 1- P( Z ≤z⁻)</em>
<em> = 1- P(Z<1.898)</em>
= 1-(0.5 +A(1.898)
= 0.5 - A(1.898)
= 0.5 -0.4641 (From Normal table)
= 0.0359
<u><em>Final answer</em></u>:-
The probability that a random sample of 10 second grade students from
= 0.0359
