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3 years ago

Suppose an item is originally

Mathematics

1 answer:

Sonbull [250]3 years ago

4 0

Answer:$21.207 or $21.21

Step-by-step explanation:

You would take $24.95 *85% (that is how much you are going to pay) and the result is your answer

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In 6th grade, there are 110 students with and 75 students without braces. What is the ratio of students without braces?

My name is Ann [436]

The ratio of students is 75:110

5 0

3 years ago

Y=sqrt(x)(8x-5) find the derivative

garri49 [273]

Answer:

$\displaystyle y' = \frac{24x - 5}{2\sqrt{x}}$

General Formulas and Concepts:

Algebra I

Exponentials [Fractions] - Are radicals
Exponential Rule [Rewrite]: $\displaystyle b^{-m} = \frac{1}{b^m}$

Calculus

Derivatives

Derivative Notation

Derivative of a constant is 0

Basic Power Rule:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Product Rule: $\displaystyle \frac{d}{dx} [f(x)g(x)]=f'(x)g(x) + g'(x)f(x)$

Step-by-step explanation:

Step 1: Define

$\displaystyle y = \sqrt{x}(8x - 5)$

Step 2: Differentiate

$\displaystyle f(x) = \sqrt{x}, \ g(x) = (8x - 5)$

Product Rule: $\displaystyle y' = \frac{d}{dx}[\sqrt{x}] \cdot (8x - 5) + \sqrt{x} \cdot \frac{d}{dx}[(8x - 5)]$
Rewrite: $\displaystyle y' = \frac{d}{dx}[x^{\frac{1}{2}}] \cdot (8x - 5) + \sqrt{x} \cdot \frac{d}{dx}[(8x - 5)]$
Basic Power Rule: $\displaystyle y' = \frac{1}{2}x^{\frac{1}{2} - 1} \cdot (8x - 5) + \sqrt{x} \cdot 1 \cdot 8x^{1 - 1}$
Simplify: $\displaystyle y' = \frac{1}{2}x^{-\frac{1}{2}} \cdot (8x - 5) + \sqrt{x} \cdot 1 \cdot 8x^{0}$
Rewrite: $\displaystyle y' = \frac{1}{2x^{\frac{1}{2}}} \cdot (8x - 5) + \sqrt{x} \cdot 1 \cdot 8$
Multiply: $\displaystyle y' = \frac{8x + 5}{2x^{\frac{1}{2}}} + 8\sqrt{x}$
Rewrite: $\displaystyle y' = \frac{8x + 5}{2\sqrt{x}} + 8\sqrt{x}$
Add/Rewrite: $\displaystyle y' = \frac{24x - 5}{2\sqrt{x}}$

3 0

3 years ago

F(x) = –2x2 + 4x + 1

ddd [48]

Answer:

x = 3/4

Step-by-step explanation:

f(x) = -2×2 +4x +1

f(x) = -4 +4x +1

f(x) = 4x -3

3 = 4x

3/4 = x

x= 3/4

3 0

3 years ago

Whats nine tenths mines three fiths

11Alexandr11 [23.1K]

To subtract fractions, we need a common denominator, which would be 10. To do this, multiply 3/5 by 2

3 * 2 = 6

5 * 2 = 10

Now subtract

$\dfrac{9}{10}-\dffrac{6}{10}=\dfrac{3}{10}$

8 0

3 years ago

Joy wants to create a box with a volume of 8 cubic units. which dimensions would work

N76 [4]

Answer:

The dimensions of the box is 2 units.

Step-by-step explanation:

Volume of cube, V = 8 cubic units

Let the length of the side is a.

So,

The volume of the cube is

$V = a^3\\\\8 = a^3\\\\a = 2 units$

So, the dimensions of the box is 2 units.

4 0

3 years ago