Answer:
See Below.
Step-by-step explanation:
We are given that ΔAPB and ΔAQC are equilateral triangles.
And we want to prove that PC = BQ.
Since ΔAPB and ΔAQC are equilateral triangles, this means that:
Likewise:
Since they all measure 60°.
Note that ∠PAC is the addition of the angles ∠PAB and ∠BAC. So:
Likewise:
Since ∠QAC ≅ ∠PAB:
And by substitution:
Thus:
Then by SAS Congruence:
And by CPCTC:
The average of 4, 9, 16, 25 and x is 2x means that;
(4+9+16+25+x)/5=2x
Multiply both side by 5
5(54+x)/5=2x(5)
54+x=10x
Subtract x to both side
54+x-x=10x-x
54=9x
Divided 9 to both side
54/9=9x/9
x=6
Check:
Substitute x with 6
(4+9+16+25+x)/5=2x
(4+9+16+25+6)/5=2(6)
60/5=12
12=12; so x=6 which marks B as the correct answer. Have a nice day!
She could give everyone an attendance sheet to mark down how much time it took them to read each week. i hope this answer has come to you pleasing
y = abˣ
20 = ab¹
20 = ab
b b
20/b = a
y = abˣ
4 = (20/b)b²
4 = 20b
20 20
¹/₅ = b
y = abˣ
20 = ¹/₅b¹
20 = ¹/₅b
¹/₅ ¹/₅
100 = b
y = abˣ
y = 100(0.2)ˣ
Thats easy the answer is b
