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melomori [17]
3 years ago
10

X(x + 5) what is the answer

Mathematics
1 answer:
frosja888 [35]3 years ago
4 0

Answer:

x^2+5x

Step-by-step explanation:

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A movie theater sells adults' tickets and children's tickets.
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Answer: $13.25 each ticket

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Please Hurry). Question: What is the value of x? (Will Mark Brainliest) Please only answer if you know it.​
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111

Step-by-step explanation:

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Cheeseburgers to go has advertised for counter help. If you take the job, you will be working 18 hours a week for $75.20 per wee
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3 years ago
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The ratio of Dawn to Mandy's savings is 6 : 7. The ratio of Mandy to Belle's savings is 2 : 3. Find the ratio of Dawn to Belle's
Mila [183]

The savings are illustrations of ratio, and the ratio of Dawn to Belle's savings in the simplest ratio is 4 : 7

<h3>How to determine the ratio?</h3>

The given ratios are:

Dawn : Mandy = 6 : 7

Mandy : Belle = 2 : 3

Multiply the second ratio by 3.5.

So, we have:

Mandy : Belle = 2 * 3.5 : 3 * 3.5

Evaluate

Mandy : Belle = 7 : 10.5

So, we have:

Dawn : Mandy = 6 : 7

Mandy : Belle = 7 : 10.5

Mandy's ratios in both equation are the same.

So, we have:

Dawn : Mandy : Belle = 6 : 7 : 10.5

Remove Mandy's ratio

Dawn : Belle = 6 : 10.5

Simplify

Dawn : Belle = 4 : 7

Hence, the ratio of Dawn to Belle's savings is 4 : 7

Read more about ratios at:

brainly.com/question/2328454

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5 0
3 years ago
A = 1011 + 337 + 337/2 +1011/10 + 337/5 + ... + 1/2021
egoroff_w [7]

The sum of the given series can be found by simplification of the number

of terms in the series.

  • A is approximately <u>2020.022</u>

Reasons:

The given sequence is presented as follows;

A = 1011 + 337 + 337/2 + 1011/10 + 337/5 + ... + 1/2021

Therefore;

  • \displaystyle A = \mathbf{1011 + \frac{1011}{3} + \frac{1011}{6} + \frac{1011}{10} + \frac{1011}{15} + ...+\frac{1}{2021}}

The n + 1 th term of the sequence, 1, 3, 6, 10, 15, ..., 2021 is given as follows;

  • \displaystyle a_{n+1} = \mathbf{\frac{n^2 + 3 \cdot n + 2}{2}}

Therefore, for the last term we have;

  • \displaystyle 2043231= \frac{n^2 + 3 \cdot n + 2}{2}

2 × 2043231 = n² + 3·n + 2

Which gives;

n² + 3·n + 2 - 2 × 2043231 = n² + 3·n - 4086460 = 0

Which gives, the number of terms, n = 2020

\displaystyle \frac{A}{2}  = \mathbf{ 1011 \cdot  \left(\frac{1}{2} +\frac{1}{6} + \frac{1}{12}+...+\frac{1}{4086460}  \right)}

\displaystyle \frac{A}{2}  = 1011 \cdot  \left(1 - \frac{1}{2} +\frac{1}{2} -  \frac{1}{3} + \frac{1}{3}- \frac{1}{4} +...+\frac{1}{2021}-\frac{1}{2022}  \right)

Which gives;

\displaystyle \frac{A}{2}  = 1011 \cdot  \left(1 - \frac{1}{2022}  \right)

\displaystyle  A = 2 \times 1011 \cdot  \left(1 - \frac{1}{2022}  \right) = \frac{1032231}{511} \approx \mathbf{2020.022}

  • A ≈ <u>2020.022</u>

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2 years ago
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