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3 years ago

Ellus Find the measure of 41. { 839 61 { « 1 = [?]

Mathematics

2 answers:

inn [45]3 years ago

8 0

ANSWER:

We know that the sum of angles of same sides in parallel lines are supplementary(180°).

So, ∠1 + 83° = 180°

∠1 = 180° - 83°
∠1 = 97°.

devlian [24]3 years ago

3 0

Answer:

180 - 83 = 97°

Step-by-step explanation:

Supplementary angles and Corresponding angles

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A card is picked at random from a deck of cards, after putting it back another card is picked at random. Are these two events d

kvv77 [185]

Answer: Independent event

Step-by-step explanation:

When two events are independent of each other, this means that the probability that one event will occurs does not in any way affects the probability of the occurrence of the other event.

For example, card is picked at random from a deck of cards, and after putting it back,thne another card is picked at random. The probability of picking the cards is not affected by each other since it is put back.

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3 years ago

Apr 23, 8:46:54 AM What is the missing term?

kipiarov [429]

Answer: -10x
Explanation: Multiply -2 by 5x

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3 years ago

Help me,,,,,,,,,thanks.......

Allisa [31]

Answer:

Your answer is D. 4/5 this is because of you had a whole pizza, and split it into five pieces, and somone takes 2 slices, there will be 3/5 of that pizza left, if they only took one, there would be 4/5, which is more pizza than a 3/5 of a pizza

Step-by-step explanation:

3 0

3 years ago

2. What inference can you make by comparing the measures of variability? I need the answer

d1i1m1o1n [39]

Answer:

16.02

Step-by-step explanation:

2. What inference can you make by comparing the measures

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7 0

3 years ago

Simplify the expression below and write it as a single logarithm:

OLEGan [10]

The simplification of 3log(x + 4) – 2log(x – 7) + 5log(x - 2) - log(x^2) is $\log \left(\frac{(x+4)^{3} \times(x-2)^{5}}{(x-7)^{2} \times x^{2}}\right)$

Solution:

Given, expression is $3 \log (x+4)-2 \log (x-7)+5 \log (x-2)-\log \left(x^{2}\right)$

We have to write in as single logarithm by simplifying it.

Now, take the given expression.

$\rightarrow 3 \log (x+4)-2 \log (x-7)+5 \log (x-2)-\log \left(x^{2}\right)$

Rearranging the terms we get,

$\left.\rightarrow 3 \log (x+4)+5 \log (x-2)-2 \log (x-7)+\log \left(x^{2}\right)\right)$

$\text { since a } \times \log b=\log \left(b^{a}\right)$

$\rightarrow \log (x+4)^{3}+\log (x-2)^{5}-\left(\log (x-7)^{2}+\log \left(x^{2}\right)\right)$

$\text { We know that } \log a \times \log b=\log a b$

$\rightarrow \log \left((x+4)^{3} \times(x-2)^{5}\right)-\left(\log \left((x-7)^{2} \times\left(x^{2}\right)\right)\right.$

$\text { We know that } \log a-\log b=\log \frac{a}{b}$

$\rightarrow \log \left(\frac{(x+4)^{3} \times(x-2)^{5}}{(x-7)^{2} \times x^{2}}\right)$

Hence, the simplified form $\rightarrow \log \left(\frac{(x+4)^{3} \times(x-2)^{5}}{(x-7)^{2} \times x^{2}}\right)$

4 0

3 years ago

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