<span> a) F' = 6 sin(x^2) = 0
x^2 = pi
x = sqrt(pi)
b) Fmax = F(1) + integral [1, pi] f(x) dx = 9.7743 </span>
Answer:
(1/2,-5/2)
Step-by-step explanation:
Take the vector u = <ux, uy> = <4, 3>.
Find the magnitude of u:
||u|| = sqrt[ (ux)^2 + (uy)^2]
||u|| = sqrt[ 4^2 + 3^2 ]
||u|| = sqrt[ 16 + 9 ]
||u|| = sqrt[ 25 ]
||u|| = 5
To find the unit vector in the direction of u, and also with the same sign, just divide each coordinate of u by ||u||. So the vector you are looking for is
u/||u||
u * (1/||u||)
= <4, 3> * (1/5)
= <4/5, 3/5>
and there it is.
Writing it in component form:
= (4/5) * i + (3/5) * j
I hope this helps. =)
Answer:
D)
Step-by-step explanation:
First we have to subtract 5 from both sides
Now, square both sides
x - 6 = 49
Now, add 6 to both sides
x - 6 +6 = 49 + 6
x = 55
