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aliya0001 [1]
3 years ago
12

a farmer has a square field that measures 100 m on a side he wants to irrigate as much of the field as he possibly can using a c

ircular irrigation system
Mathematics
1 answer:
Afina-wow [57]3 years ago
5 0
50/50 would be the answer because he dont wanna use to whole farm right 
?>
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Trevor bought 3 shirts that all cost the same amount. He also bought a jacket for $47.15. With the given information in the torn
KengaRu [80]

Answer: See explanation

Step-by-step explanation:

Your question isn't complete but let me help out. The value of each shirt will be gotten by subtracting $47.15 from the total amount paid for the shirt and jacket. Let's say the total amount paid is $90.02

Since the jacket cost $47.15, the cost of the shirts will be:

= $90.02 - $47.15

= $42.87

We would now divide the coat if the three shirts by 3. This will be:

= $42.87 ÷ 3

= $14.29

6 0
2 years ago
Simplify 5x + 3y - 2x
Blababa [14]
It is 5x+y . i think so
8 0
2 years ago
Write the inequality!! Connie’s dog Fido weighs 35 pounds. Her vet placed Fido on a diet. What inequality can you write to find
Butoxors [25]

Answer:   \frac{35-28}{x} \leq 6

Step-by-step explanation:

Let x be the average number of pounds Fido must loss.

Since, the initial weight of Fido is 35 pounds.

And, After losing the weight, the new weight of Fido in pounds = 28 pounds.

Then the time taken for losing the weight

= \frac{\text{ The weight it losses}}{\text{ Average of losing weight per month}}

= \frac{35-28}{x}

According to the question,  it must lose weight within 6 months,

Thus,   \frac{35-28}{x}\leq 6

Which is the required inequality to find the average number of pounds per month.

By solving it we, get,    x\geq \frac{7}{6}

6 0
2 years ago
Two race cars,car x an y,are at the starting point of a two km track at the same time.car x and car y make one lap every 60 s an
tino4ka555 [31]

Answer is attached.

Please check the image.

4 0
3 years ago
Which equation matches the graph below?
Oksana_A [137]

Answer:Given that the graph shows tha the functión at x = 0 is below the y-axis, the constant term of the function has to be negative. This leaves us two possibilities:

y = 8x^2 + 2x - 5 and y = 2x^2 + 8x - 5

To try to discard one of them, let us use the vertex, which is at x = -2.

With y = 8x^2 + 2x - 5, you get y = 8(-2)^2 + 2(-2) - 5 = 32 - 4 - 5 = 23 , which is not the y-coordinate of the vertex of the curve of the graph.

Test the other equation, y = 2x^2 + 8x - 5 = 2(-2)^2 + 8(-2) - 5 = 8 - 16 - 5 = -13, which is exactly the y-coordinate of the function graphed.

Step-by-step explanation:

6 0
3 years ago
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