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denis-greek [22]
3 years ago
14

How can you determine is a math question is an equation or an expression?

Mathematics
2 answers:
Tatiana [17]3 years ago
5 0

An equation will have an answer at the end like an equal sign. (Ex; 20+20=40)

An expression will NOT have an answer. (Ex; 20+20)

Mars2501 [29]3 years ago
5 0
The difference between an equation and expression in maths is that an expression is a combination of numbers, variables and symbols to be calculated. An equation contains expressions that are separated by an equals sign.
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Determine if the described set is a subspace. Assume a, b, and c are real numbers. The subset of R3 consisting of vectors of the
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This question is incomplete, the complete question is;

Determine if the described set is a subspace. Assume a, b, and c are real numbers.

The subset of R³ consisting of vectors of the form \left[\begin{array}{ccc}a\\b\\c\end{array}\right] , where abc = 0

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Answer:

Therefore; The set is not a subspace

Step-by-step explanation:

Given the data the question;

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S = {  \left[\begin{array}{ccc}a\\b\\c\end{array}\right] , where abc = 0 }

we know that a subset of R³ is a subspace if it stratifies the following properties;

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Looking at the properties, we can say that it is not a subspace

As;

         u = \left[\begin{array}{ccc}1\\1\\0\end{array}\right] ∈ S       and v = \left[\begin{array}{ccc}0\\1\\1\end{array}\right]  ∈ S

As    1×1×0=0                          0×1×1=0

But   u+v = \left[\begin{array}{ccc}1+0\\1+1\\0+1\end{array}\right] = \left[\begin{array}{ccc}1\\2\\1\end{array}\right]  ∉  S     as 1×2×1 ≠ 0

Hence, it is not closed under addition.

Therefore; The set is not a subspace

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