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Mrac [35]
3 years ago
14

-3=1/2(4d-12) what is d? And what are the steps

Mathematics
1 answer:
Nookie1986 [14]3 years ago
5 0

Answer:

d equals to 3/2

Step-by-step explanation:

1. use distributive property :

   -3= 1/2d - 6

2. get rid of six by adding it on both sides of the equation:

   -3 =1/2d - 6

  +6           + 6

________________

3=1/2d

3. multiply both sides by 1/2

3*1/2 = 1/2d *1/2

3/2=d

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Step-by-step explanation:

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What is the slope of the line that passes through the points (-6, 8) and (-9, 7)? Write your answer in simplest form.
yanalaym [24]

Answer:

m=1/3

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Identify an equation in slope intercept form for the line parallel to Y equals 4X -9 that passes through (-5,3)
Kobotan [32]

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Now compare this form with the tiven equation y=4x-9 to get the value of m.

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Now we need to find the value of b to get the equation. That parallel line passes through (-5,3).

The point intercept form of a line is,

(y-y1)=m(x-x1)

So, we can plug in the m=4, x1=-5 and y1=3 in the above equation. Hence,

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3 years ago
A professor has learned that three students in his class of 20 will cheat on the final exam. He decides to focus his attention o
balu736 [363]

Answer:

a

P(X \ge 1) = 0.509

b

P(X  \ge 1) = 0.6807

Step-by-step explanation:

From the question we are told that

   The number of students in the class is  N  =  20  (This is the population )

   The number of student that will cheat is  k =  3

   The number of students that he is focused on is  n  =  4

Generally the probability distribution that defines this question is the  Hyper geometrically distributed because four students are focused on without replacing them in the class (i.e in the generally population) and population contains exactly three student that will cheat.

Generally  probability mass function is mathematically represented as

      P(X = x) =  \frac{^{k}C_x * ^{N-k}C_{n-x}}{^{N}C_n}

Here C stands for combination , hence we will be making use of the combination functionality in our calculators  

Generally the that  he finds at least one of the students cheating when he focus his attention on four randomly chosen students during the exam is mathematically represented as

      P(X \ge 1) =  1 - P(X \le 0)

Here  

   P(X \le 0) =  \frac{ ^{3} C_0 *  ^{20 - 3} C_{4- 0}}{ ^{20}C_4}

   P(X \le 0) =  \frac{ ^{3} C_0 *  ^{17} C_{4}}{ ^{20}C_4}

   P(X \le 0) =  \frac{ 1 *  2380}{ 4845}

    P(X \le 0) =  0.491

Hence

    P(X \ge 1) =  1 - 0.491

     P(X \ge 1) = 0.509

Generally the that  he finds at least one of the students cheating when he focus his attention on six randomly chosen students during the exam is mathematically represented as

    P(X \ge 1) =  1 - P(X \le 0)

   P(X  \ge 1) =1- [  \frac{^{k}C_x * ^{N-k}C_{n-x}}{^{N}C_n}]

Here n =  6

So

    P(X  \ge 1) =1- [  \frac{^{3}C_0 * ^{20 -3}C_{6-0}}{^{20}C_6}]

    P(X  \ge 1) =1- [  \frac{^{3}C_0 * ^{17}C_{6}}{^{20}C_6}]

    P(X  \ge 1) =1- [  \frac{1  *  12376}{38760}]

    P(X  \ge 1) =1- 0.3193

    P(X  \ge 1) = 0.6807

   

5 0
3 years ago
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