1] y - 3x = -8
[2] y + 9x = 4
-3x + y = -8 9x + y = 4
Solve equation [2] for the variable y
[2] y = -9x + 4
// Plug this in for variable y in equation [1]
[1] (-9x+4) - 3x = -8
[1] - 12x = -12
// Solve equation [1] for the variable x
[1] 12x = 12
[1] x = 1
// By now we know this much :
y = -9x+4
x = 1
// Use the x value to solve for y
y = -9(1)+4 = -5
{y,x} = {-5,1}
Answer:
16.8 + (-18.6)
Step-by-step explanation:
A subtraction symbol and adding a negative are the same
Answer:
The concentration is simply 36%
Step-by-step explanation:
In this question, we are concerned with calculating the concentration of a new mixture formed from mixing some liters of each of two vinegar variants of different concentrations.
We proceed as follows;
The concentration of the new solution will contain 12% of 13L vinegar A and 70% of 9L vinegar B
13L of vinegar A will contain 13 * 12% = 13 * 0.12 = 1.56
9L of 70% vinegar B will contain 9 * 70% = 9 * 0.7 = 6.3
Now, the new mixture has a total volume of 13 + 9 = 22L
The concentration of the new mixture will thus be;
(1.56 + 6.3)/22
= 0.357 and that’s approximately 0.36 or simply 36%
The probability that the cube never lands on 3 is (D) 23.3%.
<h3>
What is probability?</h3>
- A probability formula can be used to calculate the likelihood of an occurrence by simply dividing the favorable number of possibilities by the entire number of possible outcomes.
To find the probability that the cube never lands on 3:
Given -
Required
- Probability of not landing on 3.
First, we need to get the probability of landing on 3 in a single toss.
For a number cube,
- n(3) = 1 and n(total) = 6
So, the probability is P(3) = 1/6
First, we need to get the probability of not landing on 3 in a single toss.
Opposite probability = 1.
Make P(3') the subject of the formula.
- P(3') = 1 - P(3)
- P(3') = 1 - 1/6
- P(3') = 5/6
In 8 toss, the required probability is (P(3'))⁸
This gives:
- P = (5/6)⁸
- P = 390625/1679616
- P = 0.23256803936
Approximate to 1 decimal place, P = 23.3%.
Therefore, the probability that the cube never lands on 3 is (D) 23.3%.
Know more about probability here:
brainly.com/question/25870256
#SPJ4
The correct question is given below:
A number cube is tossed 8 times. What is the probability that the cube never lands on 3?
A. 6.0%
B. 10.4%
C. 16.7%
D. 23.3%
Hello from MrBillDoesmath!
Answer: "Distributive Property", the second bullet point from the top of the list
Regards, MrB
