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Zielflug [23.3K]
2 years ago
10

Jeffrey can paint 2/3 of the classroom in 2 hours how much of the classroom can Jeffery paint in 1 hour

Mathematics
1 answer:
Maslowich2 years ago
3 0

Answer:

1/3 because 1 hour is half of 2 hours so the amount painted also has to be half if he is painting at the same rate. half of 2/3 is 1/3

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Ms Girl we on the Same Note tbh
5 0
3 years ago
Find the solution set for the following problem. 5 diminished by 3 times a number is at most 11.
leva [86]
For this case, the first thing we are going to do is define the following variable:
 x = unknown number
 We now write the following inequality:
 5-3x <= 11
 We clear x:
 5-11 <= 3x
 -6 <= 3x
 -6/3 <= x
 -2 <= x
 The solution set is:
 [-2, inf)
 Answer:
 
the solution set is:
 
[-2, inf)
4 0
3 years ago
Patrick has just finished building a pen for his new dog. The pen is 3 feet wider than it is long. He also built a doghouse to p
zalisa [80]

General Idea:

(i) Assign variable for the unknown that we need to find

(ii) Sketch a diagram to help us visualize the problem

(iii) Write the mathematical equation representing the description given.

(iv) Solve the equation by substitution method. Solving means finding the values of the variables which will make both the equation TRUE

Applying the concept:

Given: x represents the length of the pen and y represents the area of the doghouse

<u>Statement 1: </u>"The pen is 3 feet wider than it is long"

Length \; of\; the \; pen = x\\ Width \; of\; the\; pen=x+3

------

<u>Statement 2: "He also built a doghouse to put in the pen which has a perimeter that is equal to the area of its base"</u>

Area \; of\; the\; Dog \; house=y\\ Perimeter \; of\; Dog\; house=y

------

<u>Statement 3: "After putting the doghouse in the pen, he calculates that the dog will have 178 square feet of space to run around inside the pen."</u>

Area \; of \; the\; Pen - Area \;of \;the\;Dog \;House=\;Space\;inside\;Pen\\ \\ x \cdot (x+3)-y=178\\ Distributing \;x\;in\;the\;left\;side\;of\;the\;equation\\ \\ x^2+3x-y=178\Rightarrow\; 1^{st}\; Equation\\

------

<u>Statement 4: "The perimeter of the pen is 3 times greater than the perimeter of the doghouse."</u>

Perimeter\; of\; the\; Pen=3\; \cdot \; Perimeter\; of\; the\; Dog\; House\\ \\ 2(x \; + \; x+3)=3 \cdot y\\ Combine\; like\; terms\; inside\; the\; parenthesis\\ \\ 2(2x+3)=3y\\ Distribute\; 2\; in\; the\; left\; side\; of\; the\; equation\\ \\ 4x+6=3y\\ Subtract \; 6\; and \; 3y\; on\; both\; sides\; of\; the\; equation\\ \\ 4x+6-3y-6=3y-3y-6\\ Combine\; like\; terms\\ \\ 4x-3y=-6 \Rightarrow \; \; 2^{nd}\; Equation\\

Conclusion:

The systems of equations that can be used to determine the length and width of the pen and the area of the doghouse is given in Option B.

178=x^2+3x-y\\ \\ -6=4x-3y

8 0
3 years ago
Read 2 more answers
Please help, I have no idea what it's asking :')
Andre45 [30]

the answer is step by step CFE

3 0
3 years ago
Tristan is working two summer jobs, making $7 per hour babysitting and $19 per hour lifeguarding. Tristan must earn at least $21
rodikova [14]

Answer: 7bb +19 ll ≥210

Step-by-step explanation:

Hi, to answer this question we have to write an inequality:

The product of the number of hours he works babysitting (bb) and the amount he earns per hour (7); plus The product of the number of hours he works lifeguarding (ll) and the amount he earns per hour 19; must be higher or equal to the amount he must earn this week (210)

Mathematically speaking:

7 bb + 19 ll ≥210

6 0
3 years ago
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