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Zielflug [23.3K]
3 years ago
10

Jeffrey can paint 2/3 of the classroom in 2 hours how much of the classroom can Jeffery paint in 1 hour

Mathematics
1 answer:
Maslowich3 years ago
3 0

Answer:

1/3 because 1 hour is half of 2 hours so the amount painted also has to be half if he is painting at the same rate. half of 2/3 is 1/3

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If f(x)= 3x-1 and g(x)=2x-3, for which value of x does g(x)= f(2)
gregori [183]

Answer:

g(4)=f(2)

Step-by-step explanation:

f(2)=3(2)-1

f(2)=6-1

f(2)=5


We then get:

g(x)=f(2)

subsitute 5 for f(2)

g(x)=5

now solve

5=2x-3

add 3

8=2x

divide 2

4=x

so the answer is x=4 or  

g(4)=f(2)

7 0
3 years ago
Identify the terms themselves for the following expression. (separate ur terms with a comma)
Zinaida [17]
3a, 5b, -6y, 10 hope this helps
7 0
3 years ago
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To most closely estimate the difference below, would you round the numbers to the nearest ten thousand, the nearest thousand, or
zhannawk [14.2K]

Answer:

To most closely estimate the difference, I would round 62,980 to the nearest thousand, so it will be 63,000. That is because when rounding, 63,000 is large enough so that adding will be easy, and 62,980 is relatively close to 63,000.

I would round 49,625 to the nearest thousand, since it would make the subtraction easier and 49,625 is only 375 units away from 50,000.

63,000 - 50,000 = about 13,000.

Hope this helps!

6 0
3 years ago
Read 2 more answers
Q2) The following travel times were measured for vehicles traversing a 2,000 ft. segment of an arterial: Vehicle Travel Time (s)
adelina 88 [10]

Answer:

TMS = 45.78 m/s

SMS = 45.66 m/s

Step-by-step explanation:

Vehicle Travel Time (s)

1 40.5

2 44.2

3 41.7

4 47.3

5 46.5

6 41.9

7 43.0

8 47.0

9 42.6

10 43.3

Time mean speed and space mean speed are parameters used to express the speed of a group of vehicles in traffic flow.

Time mean speed is given as the average speed of all the cars

The speed for each vehicle is calculated by dividing the (2000 ft) distance by the time taken by each vehicle to complete that segment of the journey.

Let vehicle = V

Travel time = time

Speed = s

V | Time | speed (ft/s)

1 | 40.5 | 49.383

2 | 44.2 | 45.249

3 | 41.7 | 47.962

4 | 47.3 | 42.283

5 | 46.5 | 43.011

6 | 41.9 | 47.733

7 | 43.0 | 46.512

8 | 47.0 | 42.553

9 | 42.6 | 46.948

10| 43.3 | 46.189

TMS = (Σsᵢ)/N

Σsᵢ = (49.383+45.249+47.962+42.283+43.011+47.733+46.512+42.553+46.948+46.189)

Σsᵢ = 457.823

N = number of vehicles = 10

TMS = 457.823 ÷ 10 = 45.7823 = 45.782 m/s

b) Space mean speed is given as

SMS = N ÷ [Σ (1/sᵢ)]

V | Time | speed | (1/sᵢ)

1 | 40.5 | 49.383 | 0.02025

2 | 44.2 | 45.249 | 0.02210

3 | 41.7 | 47.962 | 0.02085

4 | 47.3 | 42.283 | 0.02365

5 | 46.5 | 43.011 | 0.02325

6 | 41.9 | 47.733 | 0.02095

7 | 43.0 | 46.512 | 0.02150

8 | 47.0 | 42.553 | 0.02350

9 | 42.6 | 46.948 | 0.02130

10| 43.3 | 46.189 | 0.02165

Σ (1/sᵢ) = (0.02025+0.02210+0.02085+0.02365+0.02325+0.02095+0.02150+0.02350+0.02130+0.02165)

Σ (1/sᵢ) = 0.219

SMS = 10 ÷ [Σ (1/sᵢ)] = 10 ÷ 0.219

SMS = 45.662 m/s

Hope this Helps!!!

4 0
3 years ago
Solve x<br> Log 10×=5.9<br> ×=
Alja [10]

Answer:

x=0.59

Step-by-step explanation:

because if u divide 5.9 by 10 it will give u 0.59

and isolate x

8 0
3 years ago
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