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MatroZZZ [7]
2 years ago
15

Which equations represent functions? ​

Mathematics
1 answer:
Margaret [11]2 years ago
3 0

Answer:

4x =16

Step-by-step explanation:

Hope this helps :)

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There are 96 football players at all levels at Davenport High School. If two-thirds of the players make the honor roll for their
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64 players
Reason- 2/3 of 96 = (32 x 2 = 64) telling us how many got on the list
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What is the slope of the line shown below?
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The answer is A. -2/3
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2 years ago
Roots of Quadratics 50 PTS!!!
noname [10]

The values of k for the different quadratic equation solutions are as follows

a  the equation 2x² - x + 3k = 0 has two distinct real roots

  • k < 1/24

b. the equation 5x² - 2x + (2k − 1) = 0 has equal roots

  • k = 3/5

ci the equation -x² + 3x + (k + 1) = 0 has real roots

  • k > -3.25

d the equation 3kx² - 3x + 2 = 0 has no real solutions

  • k < ± 1.633

<h3>How to solve quadratic equations to get different answers</h3>

Quadratic equations of the form ax² + bx + c = 0 is solved using the formula

-b+\frac{\sqrt{b^{2}-4ac } }{2a}     OR     -b-\frac{\sqrt{b^{2}-4ac } }{2a}

The equation b² - 4ac is called the discriminant and it is used as follows

To solve the equation and get two real roots: 2x² - x + 3k = 0

  • b² - 4ac > 0

substituting the values gives

(-1)² - 4 * 2 * 3k > 0

1 - 24k > 0

1 > 24k

divide through by coefficient of k

k < 1/24

To solve the equation and get equal roots: 5x² - 2x + (2k − 1) = 0

  • b² - 4ac = 0

substituting the values gives

(-2)² - 4 * 5 * (2k - 1) = 0

4 - 40k + 20 = 0

-40k = -24

divide through by coefficient of k

k = 3/5

To solve the equation and get real roots  -x² + 3x + (k + 1) = 0

  • b² - 4ac > 0

substituting the values gives  

(3)² - 4 * -1 * (k+1) > 0

9 + 4k + 4> 0

4k > -13

divide through by coefficient of k

k > -3.25

To solve the equation and get  no real solutions  3kx² - 3x + 2 = 0

  • b² - 4ac < 0

substituting the values gives  

(-3)² - 4 * 3k * 2 < 0

9 - 24k² > 0

9 > 24k²

divide through by coefficient of k²

k² < 24/9

k < ± 1.633

Learn more about roots of quadratic equations: brainly.com/question/26926523

#SPJ1

4 0
10 months ago
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The graph of the equation y=|x+5| is shifted 2 units up and 6 units to the right. Rewrite the equation of the new graph for the
DerKrebs [107]

Answer:

Step-by-step explanation:

To move the graph 6 units to the right, subtract 6 in the absolute value.

y=|x+5-6|

To move it up, add 2 outside the absolute value.

y=|x+5-6|+2

Now remove the absolute values since x>1.

y=x+5-6+2

y=x+1

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3 years ago
Simplify the following question
fiasKO [112]

Answer:

<em>−  2sin(b) / cos(2b)</em>

​

Step-by-step explanation:

DIFFERENTIATE W.R.T. B is a different method entirely

We simply add together the numerators and set with 2cos

then keep this number and add to sinb and square it.

then repeat initial 2 + cosb ^2 but instead of multiplying its add.

Then set the whole division to -sin (2b) squared then +1

<em> −  2cos(b)(3(sin(b))^2+(cos(b))^2)  /  −(sin(2b)) ^2 +1  </em>

​

 

5 0
2 years ago
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