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The distance between two villages is 0.625 km. Find the length in centimetres between the two villages on a map with a scale of

seropon [69]

Answer:

3125 cm

Step-by-step explanation:

The distance between two villages is 0.625 km. Find the length in centimetres between the two villages on a map with a scale of 1:5000.

We are given the scale of

1: 5000

This means

1 km = 5000 cm

Hence:

1 km = 5000cm

0.625 km = x cm

Cross Multiply

x cm = 0.625 × 5000 cm

x cm = 3125 cm

Therefore, the length in centimetres between the two villages is 3125cm

5 0

2 years ago

15.18. Find the area of the region bounded by

julia-pushkina [17]

Answer:

please mark me brainlist

Step-by-step explanation:

5 0

2 years ago

The first, third and thirteenth terms of an arithmetic sequence are the first 3 terms of a geometric sequence. If the first term

Salsk061 [2.6K]

Answer:

The first three terms of the geometry sequence would be $1$ , $5$ , and $25$ .

The sum of the first seven terms of the geometric sequence would be $127$ .

Step-by-step explanation:

Let $d$ denote the common difference of the arithmetic sequence.

Let $a_1$ denote the first term of the arithmetic sequence. The expression for the $n$ th term of this sequence (where $n\!$ is a positive whole number) would be $(a_1 + (n - 1)\, d)$ .

The question states that the first term of this arithmetic sequence is $a_1 = 1$ . Hence:

The third term of this arithmetic sequence would be $a_1 + (3 - 1)\, d = 1 + 2\, d$ .
The thirteenth term of would be $a_1 + (13 - 1)\, d = 1 + 12\, d$ .

The common ratio of a geometric sequence is ratio between consecutive terms of that sequence. Let $r$ denote the ratio of the geometric sequence in this question.

Ratio between the second term and the first term of the geometric sequence:

$\displaystyle r = \frac{1 + 2\, d}{1} = 1 + 2\, d$ .

Ratio between the third term and the second term of the geometric sequence:

$\displaystyle r = \frac{1 + 12\, d}{1 + 2\, d}$ .

Both $(1 + 2\, d)$ and $\left(\displaystyle \frac{1 + 12\, d}{1 + 2\, d}\right)$ are expressions for $r$ , the common ratio of this geometric sequence. Hence, equate these two expressions and solve for $d$ , the common difference of this arithmetic sequence.

$\displaystyle 1 + 2\, d = \frac{1 + 12\, d}{1 + 2\, d}$ .

$(1 + 2\, d)^{2} = 1 + 12\, d$ .

$d = 2$ .

Hence, the first term, the third term, and the thirteenth term of the arithmetic sequence would be $1$ , $(1 + (3 - 1) \times 2) = 5$ , and $(1 + (13 - 1) \times 2) = 25$ , respectively.

These three terms ( $1$ , $5$ , and $25$ , respectively) would correspond to the first three terms of the geometric sequence. Hence, the common ratio of this geometric sequence would be $r = 25 /5 = 5$ .

Let $a_1$ and $r$ denote the first term and the common ratio of a geometric sequence. The sum of the first $n$ terms would be:

$\displaystyle \frac{a_1 \, \left(1 - r^{n}\right)}{1 - r}$ .

For the geometric sequence in this question, $a_1 = 1$ and $r = 25 / 5 = 5$ .

Hence, the sum of the first $n = 7$ terms of this geometric sequence would be:

$\begin{aligned} & \frac{a_1 \, \left(1 - r^{n}\right)}{1 - r}\\ &= \frac{1 \times \left(1 - 2^{7}\right)}{1 - 2} \\ &= \frac{(1 - 128)}{(-1)} = 127 \end{aligned}$ .

7 0

2 years ago

A flag is 152 centimeters long.

ANTONII [103]

Divide centimeters by 100. Answer is 1.52 meters.

3 0

2 years ago

Read 2 more answers

A man retires at age 50 with $605,000 in savings. He spends his savings at a steady rate, and after 6 years of retirement, he ha

givi [52]

Since it states that he "spends his savings at a steady rate," we can assume this is a linear equation.

What we know is that he started with $605,000 and after 6 years, he used $300,000. So, we just subtract what he had originally by what he used and get $305,000. We can now make the equation as follows:

300,000=6x, where x is the amount of money he spent in one year. This equation simplifies to x=50,000, which is the amount of money he spent in one year.

Since the question asks us to tell how long it will take him to reach $100,000 in savings, we can make the equation using previous value we have found:

100,000=305,000-50,000x, where x is the number of years passed.

So, this equation solves to -205,000=-50,000x, or x=4.1

I'm not sure how you want to express your answer, but it took him 4.1 years on top of the 6 years already passed to reach $100,000. This mean 10.1 years in total.

Hope this helps!

7 0

3 years ago