1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
pychu [463]
3 years ago
11

Is triangle XYZ = ABC ? If so, name the postulate that applies. A. Congruent - ASA B. Congruent - SAS C. Might not be congruent

D. Congruent - SSS

Mathematics
1 answer:
vivado [14]3 years ago
6 0
The answer is the SAS postulate. The two triangles have two pairs of corresponding, congruent sides, and the included angles are congruent. And thus, triangles XYZ and ABC are congruent by the SAS postulate.
You might be interested in
Jimmy began deriving the quadratic formula as shown. ax² +bx +c = 0 x2+bax+ca=0 x2+bax=−ca x2+bax+(b2a)2=−ca+(b2a)2 What should
andrew11 [14]
Factor the trinomial

8 0
3 years ago
What is 154 plus 74 equal
Sergio [31]
154 + 74 = 228 is the answer.
3 0
3 years ago
Read 2 more answers
Joyce is helping to make wreaths for her Women’s Club to sell at a local bazaar. She will be making the bows for each wreath. Sh
jok3333 [9.3K]

Answer:

She can make 34 bows with 10 feet of ribbon left

Step-by-step explanation:

1.5x34=51

61-51=10 feet of ribbons left

51/1.5=x

4 0
2 years ago
Calculus 2
FinnZ [79.3K]

Answer:

See Below.

Step-by-step explanation:

We want to estimate the definite integral:

\displaystyle \int_1^47\sqrt{\ln(x)}\, dx

Using the Trapezoidal Rule, Midpoint Rule, and Simpson's Rule with six equal subdivisions.

1)

The trapezoidal rule is given by:

\displaystyle \int_{a}^bf(x)\, dx\approx\frac{\Delta x}{2}\Big(f(x_0)+2f(x_1)+...+2f(x_{n-1})+f(x_n)\Big)

Our limits of integration are from x = 1 to x = 4. With six equal subdivisions, each subdivision will measure:

\displaystyle \Delta x=\frac{4-1}{6}=\frac{1}{2}

Therefore, the trapezoidal approximation is:

\displaystyle =\frac{1/2}{2}\Big(f(1)+2f(1.5)+2f(2)+2f(2.5)+2f(3)+2f(3.5)+2f(4)\Big)

Evaluate:

\displaystyle =\frac{1}{4}(7)(\sqrt{\ln(1)}+2\sqrt{\ln(1.5)}+...+2\sqrt{\ln(3.5)}+\sqrt{\ln(4)})\\\\\approx18.139337

2)

The midpoint rule is given by:

\displaystyle \int_a^bf(x)\, dx\approx\sum_{i=1}^nf\Big(\frac{x_{i-1}+x_i}{2}\Big)\Delta x

Thus:

\displaystyle =\frac{1}{2}\Big(f\Big(\frac{1+1.5}{2}\Big)+f\Big(\frac{1.5+2}{2}\Big)+...+f\Big(\frac{3+3.5}{2}\Big)+f\Big(\frac{3.5+4}{2}\Big)\Big)

Simplify:

\displaystyle =\frac{1}{2}(7)\Big(f(1.25)+f(1.75)+...+f(3.25)+f(3.75)\Big)\\\\ =\frac{1}{2}(7) (\sqrt{\ln(1.25)}+\sqrt{\ln(1.75)}+...+\sqrt{\ln(3.25)}+\sqrt{\ln(3.75)})\\\\\approx 18.767319

3)

Simpson's Rule is given by:

\displaystyle \int_a^b f(x)\, dx\approx\frac{\Delta x}{3}\Big(f(x_0)+4f(x_1)+2f(x_2)+4f(x_3)+...+4f(x_{n-1})+f(x_n)\Big)

So:

\displaystyle =\frac{1/2}{3}\Big((f(1)+4f(1.5)+2f(2)+4f(2.5)+...+4f(3.5)+f(4)\Big)

Simplify:

\displaystyle =\frac{1}{6}(7)(\sqrt{\ln(1)}+4\sqrt{\ln(1.5)}+2\sqrt{\ln(2)}+4\sqrt{\ln(2.5)}+...+4\sqrt{\ln(3.5)}+\sqrt{\ln(4)})\\\\\approx 18.423834

6 0
3 years ago
Match the key aspect of a function's graph with its meaning.
Margarita [4]

Answer:

Part 1) Intervals of the domain where the  graph is above the x-axis (f(x) > 0)

Part 2) location on graph where input is zero  (y-intercept)

Part 3) location on graph where output is zero  (x-intercept)

Part 4) Intervals of the domain where the  graph is below the x-axis (f(x) < 0)

Step-by-step explanation:

<u><em>Verify each case</em></u>

Part 1) we have

Intervals of the domain where the  graph is above the x-axis

we know that

If the graph is above the x-axis, then the value of f(x) is positive

therefore

f(x) > 0

Part 2) we have

location on graph where input is zero  

Let

x ---> the independent variable or input value

f(x) ---> the dependent variable or output value

we know that

The y-intercept is the value of f(x) (output value) when the value of x (input value) is zero

therefore

y-intercept

Part 3) we have

location on graph where output is zero  

Let

x ---> the independent variable or input value

f(x) ---> the dependent variable or output value

we know that

The x-intercept is the value of x (input value) when the value of the function f(x) (output value) is zero

therefore

x-intercept

Part 4) we have

Intervals of the domain where the  graph is below the x-axis

we know that

If the graph is below the x-axis, then the value of f(x) is negative

therefore

f(x) < 0

5 0
3 years ago
Other questions:
  • Mr. Hammer always run 6 miles every day. The time he runs, R is inversely correlated with his speed, V. How fast was mr. Hammer
    10·1 answer
  • Steven goes to the grocery store and is looking at in Winter squash it has the mass of 1857 grams how many kilograms does the wi
    15·1 answer
  • A chemistry teacher needs to mix a 30% salt solution with a 70% salt solution to make 20 qt of a 40% salt solution. How many qua
    7·1 answer
  • 5a - 10b = 45 when b = 3
    12·2 answers
  • Find the exact value of each trigonometric function
    11·1 answer
  • Identify the parts of the expression 8+6q+q. Write a word expression
    5·1 answer
  • A coconut is a fruit that is made up of a hard outer shell that is spherical. Inside, there is a thick layer of coconut meat tha
    12·1 answer
  • Please i really need help!!! thnakss
    14·1 answer
  • Erin says the first step is to set Latex: 2x+7
    9·1 answer
  • What do I do with e^y in the differential equation dy/dt =(2t)/(e^y)?
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!