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Margaret [11]
3 years ago
12

Using the periodic table, determine the ion charges of the following elements if valence electrons were removed or added to reac

h the octet. barium = iodine = potassium = aluminum =
Chemistry
2 answers:
Svetllana [295]3 years ago
8 0

Answer: barium's charge would be +2, iodine's -1, potassium's +1, and aluminum's +3.  

Explanation:

Dafna1 [17]3 years ago
5 0
Hi, there!

The answer to your question is as follows: 
Given that the valence electrons were removed or added to the following elements to fulfill the octet, barium's charge would be +2, iodine's -1, potassium's +1, and aluminum's +3.  

I hope this helps!
You might be interested in
If I have 13 protons and 12 electrons what is my charge?
Mnenie [13.5K]

Answer:

The charge would be +1

Explanation:

Protons have a positive charge while electrons have a negative charge. Therefore, it's simple subtraction. In every case, subtract the number of electrons from the number of protons.

13 - 12 = 1

Therefore the charge is +1

Here's one more example:

If the element chromium (Cr) has 24 protons and 28 electrons, what is its charge? Remember that protons have a positive charge and electrons have a negative charge.

24 - 28 = -4

Charge = -4

It would be written as followed when associating charge with a specific element: Cr^{-4}

If an element has a neutral charge, that means the number of protons and neutrons are the same. If you look at the periodic table of elements, all of the elements listed have a neutral charge. The 0 isn't showed in the corner because it isn't necessary.

Bonus Information:

This isn't related to your question, but I've come across confusions when it comes to particles. Remember that protons (+) and electrons (-) are the only particles that have a charge, therefore, as it says in it's name, neutrons are neutral or have no charge. Neutrons do not contribute to charge, but they do contribute to the <em>mass</em> of an atom. So the number of protons added to the number of neutrons equate to the mass of an atom. Electrons have mass, but it's so miniscule and insignificant that it doesn't even contribute to the overall mass of the atom, so don't count those.

Remember:

C = p - e

M = p + n

C = atomic charge, M = atomic mass, p =protons, n = neutrons, e = electrons

I hope this helps!

7 0
3 years ago
Blank moles of carbon dioxide are required to make 7.2 moles of glucose. A plant using 618 grams of carbon dioxide and plenty of
Virty [35]

Answer:

43.2 moles of carbon dioxide are required and 421g of glucose could be produced

Explanation:

Based on the reaction:

6CO2 + 6H2O → C6H12O6 + 6O2

1 mole of glucose, C6H12O6, requires 6 moles of carbon dioxide. 7.2moles of glucose requires:

7.2mol C6H12O6 * (6mol CO2 / 1mol C6H12O6) =

<h3>43.2 moles of carbon dioxide are required</h3><h3 />

618g of CO2 -Molar mass: 44.01g/mol- are:

618g * (1mol / 44.01g) = 14.04moles CO2

Moles C6H12O6:

14.04moles CO2 * (1mol C6H12O6 / 6mol CO2) = 2.34moles C6H12O6

Mass glucose -Molar mass: 180.156g/mol-

2.34moles C6H12O6 * (180.156g / mol) =

<h3>421g of glucose could be produced</h3>
7 0
3 years ago
Calculate the molarity of a solution that contains 3.11 mol of NaNO3 dissolved in 2.50 L. Enter your answer in the provided box.
rusak2 [61]

Answer:

Molarity of a solution that contains 3.11 mol of NaNO3 is 1,24 M

Explanation:

We understand molarity as the number of moles of solute that are contained in 1 L of solution, then if in a solution of 2.50 L we have 3.11 moles, it remains to calculate how many moles do we have in 1 liter.

2,50 L .......... 3,11 moles

1 L .................. x

X = ( 1 L x 3,11 moles) / 2,50 L = 1,24

8 0
3 years ago
Propanoic acid, ch3ch2cooh, has a pka =4.9. draw the structure of the conjugate base of propanoic acid and give the ph above whi
xenn [34]

Conjugate base of Propanoic acid (CH_{3}CH_{2}COOH is propanoate where -COOH group gets converted to -COO^{1-}. The structure of conjugate base of Propanoic acid is shown in the diagram.

The p^{H} above which 90% of the compound will be in this conjugate base form can be determined using Henderson's equation as propanoic acid is weak acid and it can form buffer solution on reaction with strong base.

p^{H}= p^{k_{a}+ log\frac{[Conjugate base]}{[acid]}=4.9+log\frac{90}{10}=5.85

As 90% conjugate base is present, so propanoic acid present 10%.

8 0
4 years ago
The sodium isotope with 13 neutrons. Express your answer as an isotope
wariber [46]

Answer:

          \large\boxed{\large\boxed{^{24}_{11}Na}}

Explanation:

The question is asking to write the <em>isotopic symbol </em>of the form ^A_ZX for the <em>sodium isotope with 13 neutrons</em>.

In general, the isotopic symbol in the given form shows:

  • The element's chemical symbol: X

  • A: mass number of the isotope, written as a superscript to the left of the element's simbol, and

        A = number of protons + number of neutrons

  • Z: atomic number of the isotope, written as a subscript to the left of the elements's symbol,

        Z = number of protons

The atomic symbol of sodium is Na.

The atomic number, or number of protons, is the same for every isotope of the element, and you can find it in any periodic table. Tha atomic number of sodium is 11. Thus:

  • Z = 11

The mass number is the number of protons plus neutrons, hence:

  • A = 11 + 13 = 24

Now you can write the isotope symbol for the sodium isotope with 13 neutrons:

         ^{24}_{11}Na

6 0
4 years ago
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