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nirvana33 [79]
3 years ago
8

Blank moles of carbon dioxide are required to make 7.2 moles of glucose. A plant using 618 grams of carbon dioxide and plenty of

water can make
Chemistry
1 answer:
Virty [35]3 years ago
7 0

Answer:

43.2 moles of carbon dioxide are required and 421g of glucose could be produced

Explanation:

Based on the reaction:

6CO2 + 6H2O → C6H12O6 + 6O2

1 mole of glucose, C6H12O6, requires 6 moles of carbon dioxide. 7.2moles of glucose requires:

7.2mol C6H12O6 * (6mol CO2 / 1mol C6H12O6) =

<h3>43.2 moles of carbon dioxide are required</h3><h3 />

618g of CO2 -Molar mass: 44.01g/mol- are:

618g * (1mol / 44.01g) = 14.04moles CO2

Moles C6H12O6:

14.04moles CO2 * (1mol C6H12O6 / 6mol CO2) = 2.34moles C6H12O6

Mass glucose -Molar mass: 180.156g/mol-

2.34moles C6H12O6 * (180.156g / mol) =

<h3>421g of glucose could be produced</h3>
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\Delta T_f=\text{freezing point of acetic acid}-\text{Freezing point of solution}

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\Delta T_f=iK_fm

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Putting values in above equation, we get:

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Hence, the boiling point of solution is 118.2°C

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