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3 years ago

Which equation is parallel to the line y= -5/7x - 7

Mathematics

1 answer:

Lunna [17]3 years ago

3 0

Answer:

5x + 7y = -42

Step-by-step explanation:

This question will be a little easier to answer if we change the form of the original equation from slope intercept to standard form:

$y=(-5/7)x-7\\(5/7)x+y=-7\\5x+7y=-49$

All parallel lines have the same slope, but what does that mean when our equation's in standard form. Well, slope only depends on the coefficients of the x and y terms, so any equation of a line in standard form with 5x + 7y on the left side will be parallel to the one in the problem. Looking through the possible choices, B. 5x + 7y = -42 is the only one that works.

Using desmos to check our work, we can see that the two lines are actually parallel!

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Can someone please help me in this question

Pie

Step-by-step explanation:

a) Let y = f(x) = 3x - 2x^2

f(-2) = 3(-2) - 2(-2)^2 = p

= -6 - 8

= -14

= p

f(2.5) = 3(2.5) - 2(2.5)^2 = q

= 7.5 - 12.5

= -5

= q

b) graphing

c) From the graph, you should be able to verify the following:

i) f(0.5) = 3(0.5) - 2(0.5)^2 = 1

ii) 0.5 = 3x - 2x^2 or x = 1.3, 0.2

iii) the maximum occurs at

f(0.75) = 1.125

d) the equation for the line of symmetry is x = 0.75

4 0

3 years ago

Please help, I've been doing math since the time I woke up, with no breaks. I'm brain dead rn. It's all timed.

Yuki888 [10]

The correct answer is A and D

8 0

3 years ago

Set F1 = 5N at 0 degrees, F2= 5N at 90 degrees, F3 = 5N at 270 degrees and run the simulation. Using trigonometry, what net forc

Mrac [35]

Answer: find the solution in the explanation

Step-by-step explanation:

Let's use resolution of forces by resolving into x - component and y- component.

X - component.

Sum of forces = F1 - F3 - F4cos 15

Sum of forces = 0

5 - 5 - 0.97F4 = 0

- 0.97 F4 = 0

F4 = 0

Y - component

Sum of forces = F2 + F4 sin 15

Sum of forces = 0

5 + 0.26F4 = 0

0.26 F4 = -5

F4 = -5/0.26

F4 = -19.23 N

Simulating F4 back into the equation

Sum of forces = F1 - F3 - F4cos 15

- F4cos Ø = 0

- (-19.23) cos Ø = 0

Cos Ø = 0

Ø = 1

Does the angle formed approximate 15 degrees ? NO

7 0

4 years ago

Three Texas drovers met on a highway and began to dicker as follows:

Alik [6]

Answer:

Jim's: 7
Duke's: 21
Hank's: 11

Step-by-step explanation:

Let J, D, and H represent the drove sizes of Jim, Duke, and Hank.

2(H -6 + 1) = (J +6 -1) . . . . . Hank's offer

3(D -14 +1) = (H +14 -1) . . . . Duke's offer

6(J -4 +1) = (D +4 -1) . . . . . . Jim's offer

These equations can be simplified to ...

2H - J = 15

3D - H = 52

6J - D = 21

Solution

Adding twice the second equation to the first gives ...

2(3D -H) +(2H -J) = 2(52) +(15)

6D -J = 119

Adding 6 times the third equation to this one gives ...

6(6J -D) +(6D -J) = 6(21) +(119)

35J = 245

J = 7

Using this value in the third equation gives ...

6(7) -D = 21

42 -21 = D = 21

Using the value of J in the first equation gives ...

2H -7 = 15

H = (15 +7)/2 = 11

Then the solution is (J, D, H) = (7, 21, 11).

Jim's drove had 7 animals; Duke's drove had 21 animals; Hank's drove had 11 animals.

5 0

3 years ago

LekaFEV [45]

Answer: $y-1=\dfrac32(x+3)$

Step-by-step explanation:

Slope of a line passes through (a,b) and (c,d) = $\dfrac{d-b}{c-a}$

In graph(below) given line is passing through (-2,-4) and (2,2) .

Slope of the given line passing through (-2,-4) and (2,2) = $\dfrac{-4-2}{-2-2}=\dfrac{-6}{-4}=\dfrac{3}{2}$

Since parallel lines have equal slope . That means slope of the required line would be .

Equation of a line passing through (a,b) and has slope m is given by :_

(y-b)=m(x-a)

Then, Equation of a line passing through(-3, 1) and has slope = is given by

$(y-1)=\dfrac32(x-(-3))\\\\\Rightarrow\ y-1=\dfrac32(x+3)$

Required equation: $y-1=\dfrac32(x+3)$

8 0

3 years ago