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padilas [110]
3 years ago
11

Which expression is equivalent to -32^3/5

Mathematics
1 answer:
Tanya [424]3 years ago
5 0

Answer:

Step-by-step explanation:

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Cottage cheese is being sold in different size containers. The sizes and prices are given below:
BabaBlast [244]
If the point of the assignment is to get the most amount of cheese per dollar the answer is a.

You just divide the price with the number of ounces you buy and that will give you the price per ounce.

a = 5/(4*5) = $0.25 per ounce
b = 3.24/12 = $0.27 per ounce
c = 4.19/16 = 0.261875

therefore a is the best bang for the buck

Hope this helps :)
7 0
3 years ago
Read 2 more answers
A gardener plants 250 sunflower seeds and 210 germinate. Find the probability that a sunflower seed will germinate.
Anni [7]

Answer:

There is a 84% probability that the seed will germinate. (Poor plants)

Step-by-step explanation:

250 = 100%

210 = x

250x = 21000

x = 84

7 0
3 years ago
PLEASE HELP !! IT WOULD BE GREATLY APPREACIATED ! I DONT KNOW HOW TO DO THIS
serg [7]

(A) Bella's TV ratio of sides: 36"/27" = 1.333...

Lenny's: 52"/29.25" = 1.777...

Bella's and Lenny's TVs are NOT similar - their side ratios are different. Bella's is 4:3 while Lenny's is close to 16:9.

(B) Bella's TV has an exact ratio of 4:3 (36/27=4/3) and so is the older type.

Lenny's TV has a ratio of 52"/29.25". Divide both 52 and 29.25 by 3.25 to get 16/9, or 16:9. So Lenny's is the newer type.


4 0
3 years ago
Write an equation of the line that passes through (2,3) and is perpendicular to the line shown
kow [346]

Answer:

(2,3)

Step-by-step explanation:

(2,3) is your answer

5 0
3 years ago
Read 2 more answers
The amounts of nicotine in a certain brand of cigarette are normally distributed with a mean of 0.917 g and a standard deviation
Nutka1998 [239]

Answer:

z = \frac{0.872-0.917}{\frac{0.303}{\sqrt{37}}}= -0.903

And we can find this probability to find the answer:

P(z

And using the normal standar table or excel we got:

P(z

Step-by-step explanation:

Let X the random variable that represent the amounts of nocatine of a population, and for this case we know the distribution for X is given by:

X \sim N(0.917,0.303)  

Where \mu=0.917 and \sigma=0.303

We have the following info from a sample of n =37:

\bar X= 0.872 the sample mean

And we want to find the following probability:

P(\bar X \leq 0.872)

And we can use the z score formula given by;

z=\frac{x-\mu}{\frac{\sigma}{\sqrt{n}}}

And if we find the z score for the value of 0.872 we got:

z = \frac{0.872-0.917}{\frac{0.303}{\sqrt{37}}}= -0.903

And we can find this probability to find the answer:

P(z

And using the normal standar table or excel we got:

P(z

6 0
3 years ago
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