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2 years ago

Which of the following expressions are equivalent to 4+ (14 – 2) CHOOSE 3

Mathematics

1 answer:

Vanyuwa [196]2 years ago

7 0

Answer:

The last 3, so C, D, and E.

Step-by-step explanation:

4+(14-2) = 16

See which of the following equations in the image create the value of 16 to find which ones are equivalent.

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What is 1.6 powered by 2

ss7ja [257]

Answer:

2.56

Step-by-step explanation:

1.6^2 = 1.6 * 1.6 = 2.56

7 0

2 years ago

NEED HELP FAST!!!!!

slava [35]

5p-4p-8=-2+3

Combine like terms
p-8= 1

Add 8 to both sides to isolate p
p=9

Final answer: 1 solution only, p=9

8 0

3 years ago

Read 2 more answers

Consider two independent tosses of a fair coin. Let A be the event that the first toss results in heads, let B be the event that

aliina [53]

Answer with Step-by-step explanation:

We are given that two independent tosses of a fair coin.

Sample space={HH,HT,TH,TT}

We have to find that A, B and C are pairwise independent.

According to question

A={HH,HT}

B={HH,TH}

C={TT,HH}

$A\cap B=$ {HH}

$B\cap C$ ={HH}

$A\cap C$ ={HH}

P(E)= $\frac{number\;of\;favorable\;cases}{total\;number\;of\;cases}$

Using the formula

Then, we get

Total number of cases=4

Number of favorable cases to event A=2

$P(A)=\frac{2}{4}=\frac{1}{2}$

Number of favorable cases to event B=2

Number of favorable cases to event C=2

$P(B)=\frac{2}{4}=\frac{1}{2}$

$P(C)=\frac{2}{4}=\frac{1}{2}$

If the two events A and B are independent then

$P(A)\cdot P(B)=P(A\cap B)$

$P(A\cap)=\frac{1}{4}$

$P(B\cap C)=\frac{1}{4}$

$P(A\cap C)=\frac{1}{4}$

$P(A)\cdot P(B)=\frac{1}{2}\cdot \frac{1}{2}=\frac{1}{4}$

$P(B)\cdot P(C)=\frac{1}{4}$

$P(A)\cdot P(C)=\frac{1}{4}$

$P(A)\cdot P(B)=P(A\cap B)$

Therefore, A and B are independent

$P(B)\cdot P(C)=P(B\cap C)$

Therefore, B and C are independent

$P(A\cap C)=P(A)\cdot P(C)$

Therefore, A and C are independent.

Hence, A, B and C are pairwise independent.

6 0

3 years ago

Solve for the missing sides 30-60-90 triangle show work please and thank you

Alex_Xolod [135]

Answer:

$x=8\sqrt{3}$

$y=16$

$x=3$

$y=3\sqrt{3}$

Step-by-step explanation:

The sides of a (30 - 60 - 90) triangle follow the following proportion,

$a-a\sqrt{3}-2a$

Where (a) is the side opposite the (30) degree angle, ( $a\sqrt{3}$ ) is the side opposite the (60) degree angle, and (2a) is the side opposite the (90) degree angle. Apply this property for the sides to solve the two given problems,

It is given that the side opposite the (30) degree angle has a measure of (8) units. One is asked to find the measure of the other two sides.

The measure of the side opposite the (60) degree side is equal to the measure of the side opposite the (30) degree angle times ( $\sqrt{3}$ ). Thus the following statement can be made,

$x=8\sqrt{3}$

The measure of the side opposite the (90) degree angle is equal to twice the measure of the side opposite the (30) degree angle. Therefore, one can say the following,

$y=16$

In this situation, the side opposite the (90) degree angle has a measure of (6) units. The problem asks one to find the measure of the other two sides,

The measure of the side opposite the (60) degree angle in a (30-60-90) triangle is half the hypotenuse times the square root of (3). Therefore one can state the following,

$y=3\sqrt{3}$

The measure of the side opposite the (30) degree angle is half the hypotenuse (the side opposite the (90) degree angle). Hence, the following conclusion can be made,

$x=3$

6 0

3 years ago

What is the answer to this calculus problem???<br><img src="https://tex.z-dn.net/?f=%20%5Cfrac%7Bd%7D%7Bdx%7D%20%28e%20%7B%7D%5E

Len [333]

Answer:

see explanation

Step-by-step explanation:

Differentiate using the product rule

Given y = f(x)g(x), then

$\frac{dy}{dx}$ = f(x). g'(x) + g(x). f'(x)

here f(x) = $e^{x}$ ⇒ f'(x) = $e^{x}$

g(x) = cosx ⇒ g'(x) = - sinx

Hence

$\frac{dy}{dx}$ = $e^{x}$ (- sinx) + cosx $e^{x}$

= $e^{x}$ cosx - $e^{x}$ sinx

3 0

2 years ago