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3 years ago

Let’s see who knows this short quiz

Mathematics

1 answer:

Zanzabum3 years ago

5 0

Answer:

1..JANE FISH FIRST.

2..BEN WAS LAST.

3..20 MIN AHEAD OF RITA

4..BEN WAS 25 MIN BEHIND ALL AND 5 MIN BEHIND RITA

5..9.45 IS THE AVERAGE TIME OF 3 STUDENTS

Step-by-step explanation:

<h3>MARK AS BRAINLIAST</h3>

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Abby is touring China for four days. The car rental is $38.15 per day plus 12 1/2 cents per mile. If Abby drives 380.5 miles, ho

abruzzese [7]

Answer:

200.1625

Step-by-step explanation:

38.15 × 4 + .125 × 380.5

4 0

3 years ago

Read 2 more answers

The probability that an egg on a production line is cracked is 0.01. Two eggs are selected at random from the production line. F

musickatia [10]

Answer:

$P(X \geq 1)=1-P(X$

$P(X=0)=(2C0)(0.01)^0 (1-0.01)^{2-0}=0.9801$

And replacing we got:

$P(X \geq 1) = 1-0.9801 = 0.0199$

Step-by-step explanation:

Let X the random variable of interest "number of craked eggs", on this case we now that:

$X \sim Binom(n=2, p=0.01)$

The probability mass function for the Binomial distribution is given as:

$P(X)=(nCx)(p)^x (1-p)^{n-x}$

Where (nCx) means combinatory and it's given by this formula:

$nCx=\frac{n!}{(n-x)! x!}$

And we want to find this probability:

$P(x \geq 1)=1-P(X$

And we can find the probability:

$P(X=0)=(2C0)(0.01)^0 (1-0.01)^{2-0}=0.9801$

And replacing we got:

$P(X \geq 1) = 1-0.9801 = 0.0199$

5 0

3 years ago

A new catalyst is being investigated for use in the production of a plastic chemical. Ten batches of the chemical are produced.

zzz [600]

Answer:

$CI=(66.54,78.46)$

Step-by-step explanation:

Given : A new catalyst is being investigated for use in the production of a plastic chemical. Ten batches of the chemical are produced. The mean yield of the 10 batches is 72.5% and the standard deviation is 5.8%. Assume the yields are independent and approximately normally distributed.

To find : A 99% confidence interval for the mean yield when the new catalyst is used ?

Solution :

Let X be the yield of the batches.

We have given, n=10 , $\bar{X}=72.5\%$ , s=5.8%