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3 years ago

5

A bag has yellow, red, green, blue, black, and white marbles. There are 5 of each color in the bag. What fraction of the marbles

, in simplest form, are not black or white?

1 answer:

Ahat [919]3 years ago

8 0

Answer:

2/3

Step-by-step explanation:

Have a great day

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Solve the system by graphing.<br><br> 3x+8y=16<br><br> 3x+8y=-64

Gnesinka [82]

<em>-3x-y=10</em>

<em>4x-4y=8</em>

<em>or</em>

<em>y = -3x - 10 </em>

<em>P(0,-10) and P(-2, -4) on this line: Plot and connect with the Line.</em>

<em></em>

<em> </em>

<em>y = x - 2</em>

<em>P(0, -2) and (2,0) on this line: Plot and connect with the Line.</em>

<em>P(-2,-4) is the ordered pair that is the solution for this system of EQs</em>

<em>On may CHECK by substituting x= -2 and y = -4 into the EQs of these Lines</em>

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<em>Hope this helps!!!</em>

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3 years ago

PLEASE I NEED HELP WITH THE BOTTOM QUESTION

GenaCL600 [577]

Answer:

6/25

Step-by-step explanation:

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3 years ago

Where are three places you might find line segments in the real world?

egoroff_w [7]

Answer:

<u><em>Real-world examples of line segments are a pencil, a baseball bat, the cord to your cell phone charger, the edge of a table, etc. Think of a real-life quadrilateral, like a chessboard; it is made of four line segments</em></u>

Step-by-step explanation:

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3 years ago

The attention span of children (ages 3 to 5) is claimed to be Normally distributed with a mean of 15 minutes and a standard devi

Agata [3.3K]

Answer:

If the observed sample mean is greater than 17.07 minutes, then we would reject the null hypothesis.

Step-by-step explanation:

We are given the following in the question:

Population mean, μ = 15 minutes

Sample size, n = 10

Alpha, α = 0.05

Population standard deviation, σ = 4 minutes

First, we design the null and the alternate hypothesis

$H_{0}: \mu = 15\text{ minutes}\\H_A: \mu > 15\text{ minutes}$

Since the population standard deviation is given, we use one-tailed z test to perform this hypothesis.

Formula:

$z_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{\sigma}{\sqrt{n}} }$

Now, $z_{critical} \text{ at 0.05 level of significance for one tail} = 1.64$

Thus, we would reject the null hypothesis if the z-statistic is greater than this critical value.

Thus, we can write:

$z_{stat} = \displaystyle\frac{\bar{x} - 15}{\frac{4}{\sqrt{10}} } > 1.64\\\\\bar{x} - 15>1.64\times \frac{4}{\sqrt{10}}\\\bar{x} - 15>2.07\\\bar{x} > 15+2.07\\\bar{x} > 17.07$

Thus, the decision rule would be if the observed sample mean is greater than 17.07 minutes, then we would reject the null hypothesis.

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4 years ago

Article on sale original price percent discount

Thepotemich [5.8K]

The 1/3% would equal .33% hopefully that helps at least a little

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4 years ago