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lilavasa [31]
3 years ago
9

Find the missing length of the triangle. If necessary, round your answer to the nearest tenth

Mathematics
2 answers:
lisov135 [29]3 years ago
8 0

Answer:

x = 30

Step-by-step explanation:

a^{2} = c^{2} - b^{2}

a^{2} = 50^{2} - 40^{2}

a^{2} = 2500 - 1600

a^{2} = 900

\sqrt{a^{2}} = \sqrt{900}

a = 30

Amiraneli [1.4K]3 years ago
4 0

Answer:

30

Step-by-step explanation:

Since this is a right triangle, we can use the Pythagorean theorem to find the missing side

a^2 +b^2 = c^2  where a and b are the sides and c is the hypotenuse

x^2 + 40^2 = 50^2

x^2 +1600 = 2500

x^2 = 2500-1600

x^2 = 900

Take the square root of each side

sqrt(x^2) = sqrt(900)

x = 30

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Which is the equation of a hyperbola with directrices at x = ±2 and foci at (5, 0) and (−5, 0)? y squared over 40 minus x square
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The equation of the hyperbola with directrices at x = ±2 and foci at (5, 0) and (−5, 0) is \frac{x^2}{10} + \frac{y^2}{15} = 1

<h3>How to determine the equation of the hyperbola?</h3>

The given parameters are:

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The foci of a hyperbola are represented as:

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The center is:

Center = (h,k)

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Directrix, x = h ± a²/c

By comparison, we have:

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a²/c = 2

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b² = c² - a²

This gives

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\frac{(x - k)^2}{a^2} + \frac{(y - h)^2}{b^2} = 1

So, we have:

\frac{(x - 0)^2}{10} + \frac{(y - 0)^2}{15} = 1

Evaluate

\frac{x^2}{10} + \frac{y^2}{15} = 1

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