Answer:
x = 2
Step-by-step explanation:
Given a line parallel to a side of a triangle and intersecting the other 2 sides then it divides those sides proportionally, that is
=
( cross- multiply )
6x = 4(x + 1)
6x = 4x + 4 ( subtract 4x from both sides )
2x = 4 ( divide both sides by 2 )
x = 2
Answer:
He does not have enough money to buy the hat.
Step-by-step explanation:
First find out how much he spent on the ticket:
He spent $62 on the ticket, so he has $90 - $62 = $28 remaining. Now find out how much of that he spent at the concession stand:
He spent $12 at the concession stand, so he has $28 - $12 = $16 remaining. He does not have enough to buy the $18 hat.
To complete the table we must carefully observe the keypad, we will notice that each number is equivalent to 3 letters of the alphabet except the numbers 7 and 9 which have 4 letters each.
<h3>How does the keypad work?</h3>Previously, cell phone keypad had a different layout than today. The numbers were related to the letters of the alphabet and the number key was pressed according to the letters that were related.
For example, if you wanted to type the letter B, you would have to press the number 2 key twice.
The relationship of numbers and letters was distributed as follows:
According to the above, the table would be completed as follows.
Note: This question is incomplete because there is some missing information. Here is the missing information:
1. Complete this table to show the relation from letter to number.
Learn more about keypad in: brainly.com/question/1156254
Answer:
2x - y - 3z = 0
Step-by-step explanation:
Since the set
{i, j} = {(1,0), (0,1)}
is a base in
and F is linear, then
<em>{F(1,0), F(0,1)} </em>
would be a base of the plane generated by F.
F(1,0) = a+b = (2i-2j+k)+(i+2j+k) = 3i+2k
F(0,1) = a+c = (2i-2j+k)+(2i+j+2k) = 4i-j+3k
Now, we just have to find the equation of the plane that contains the vectors 3i+2k and 4i-j+3k
We need a normal vector which is the cross product of 3i+2k and 4i-j+3k
(3i+2k)X(4i-j+3k) = 2i-j-3k
The equation of the plane whose normal vector is 2i-j-3k and contains the point (3,0,2) (the end of the vector F(1,0)) is given by
2(x-3) -1(y-0) -3(z-2) = 0
or what is the same
2x - y - 3z = 0