Answer:
0
Step-by-step explanation:
any log with a base of one and it becomes logv5 (1) after logv5(logV3 (3) because log3(3) equal one so then logv5 (1) is 0
<h3>Answer:</h3>
y = 2·sec((x -3π/2)/2) -4
<h3>Explanation:</h3>
The general shape of the curve suggests the parent function is a secant or cosecant function. Here, we choose to use the secant. It might help to familiarize yourself with the graph of a secant function (shown in the second attachment).
The centerline between the local maximum and local minimum is at -4, so that is the vertical offset.
The distance between that centerline and a local maximum or minimum is 2 units, so the vertical expansion factor is 2.
The horizontal distance between the local maximum and local minimum is 2π, so represents a horizontal expansion by a factor of 2.
The location of the local minimum is at x=3π/2, so that represents the horizontal offset.
The form of the function with these various transformations is ...
... g(x) = (vertical scale factor) × f((x - (horizontal offset))/(horizontal expansion factor)) - (vertical offset)
Filling in the function and the various values, we get ...
... y = 2·sec((x -3π/2)/2) -4
Step-by-step explanation:
we don't see the complex numbers.
so, we cannot check their distances.
a suspicion, though.
sqrt(45) a distance between 2 complex numbers is
sqrt(a² + b²).
so,
a² + b² = 45
a nice combination of whole square numbers would be 6 and 3.
6² + 3² = 36 + 9 = 45
if that is the case, then that would mean one of the following committed numbers
6 + 3i
3 + 6i
-6 + 3i
6 - 3i
-6 - 3i
-3 + 6i
3 - 6i
-3 - 6i
one of these numbers must be the result of the subtraction of the 2 provided complex numbers.
remember
(a + bi) - (c + di) = a-c + (b-d)i
Draw a ray with one endpoint