Answer:
Step-by-step explanation:
If we are to find q(p(x)), we are to start at the innermost part of the problem which is p(x). Take the function p(x) and fill it into q(x) every place you see an x:
is the composition of p into q. Now all we have left to do is simplify.
Then we have to finally multiply in the 2 to get:
Answer:
x = 3.24, x = -1.24
Step-by-step explanation:
The standard form for a quadratic equation is . For your equation a = 1, b = -2, c = -4. The quadratic formula you will be using is
.
Plug in a = 1, b = -2, and c = -4 into the formula.
We'll do the top part first:
Apply rule
Apply exponent rule if
is even
Multiply the numbers
Add
The prime factorization of 20 is
20 divides by 2. <em>20 = 10 * 2</em>
<em /><em />
10 divides by 2. <em>10 = 5 * 2</em>
<em /><em />
2 & 5 are prime numbers so you don't need to factor them anymore
Apply radical rule
Apply radical rule ;
Because of the you have to separate the solutions so that one is positive and the other is negative.
Positive x:
Apply rule
Multiply
Factor and rewrite it as
. Factor out 2 because it is the common term.
.
Divide 2 by 2
or
(You'll probably have to use a calculator for the square root of 5)
^Repeating the process of positive x for negative x in order to get or
Answer:
The product of the monomials is 2304
Step-by-step explanation:
* <em>Lets explain how to solve the problem</em>
- We need to find the product of the monomials (8x 6y)² and
- At first lets solve the power of the first monomial
- Because the power 2 is on the bracket then each element inside the
bracket will take power 2
∵ (8x 6y)² = (8)²(x)²(6)²(y)²
∵ (8)² = 64
∵ (x)² = x²
∵ (6)² = 36
∵ (y)² = y²
∴ (8x 6y)² = [64x² × 36y²]
∵ 64 × 36 = 2304 x²y²
∴ The first monomial is 2304 x²y²
∵ The first monomial is 2304 x²y²
∵ The second monomial is
- Lets find their product
- Remember in multiplication if two terms have same bases then we
will add their powers
∵ [2304 x²y²] × [ ] =
2304 [ ] [
]
∵ =
=
∵ =
=
∴ [2304 x²y²] × [ ] = 2304
The product of the monomials is 2304