Okay first make sure you change negative 8 to a positive 8.
Set the problem up 8 -11 -49 899 -2506
__________________
8 -11 -49 899 -2506
-88 -1096 -1576
____________________
-11 -137 -197 -4082
Your answer will be
-11x^3 - 137x^2 - 197x - 4082
You need two terms that multiply to (12x-4). The term on the outside needs to be a common multiple of 12 and 4. The common factors are 1, 2, and 4. Here are the following possible dimensions:
1(12x-4)
2(6x-2)
4(3x-1)
Hope this helps.
Answer:
75 in
Step-by-step explanation:
Answer:
We need a sample size of at least 719
Step-by-step explanation:
We have that to find our
level, that is the subtraction of 1 by the confidence interval divided by 2. So:

Now, we have to find z in the Ztable as such z has a pvalue of
.
So it is z with a pvalue of
, so 
Now, find the margin of error M as such

In which
is the standard deviation of the population and n is the size of the sample.
How large a sample size is required to vary population mean within 0.30 seat of the sample mean with 95% confidence interval?
This is at least n, in which n is found when
. So






Rouding up
We need a sample size of at least 719