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beks73 [17]
3 years ago
6

HELPPPPP ASAPPPPPPPPPPPPPPPP PLSSS

Mathematics
1 answer:
balandron [24]3 years ago
4 0

Answer:

B) 2\ sq.rt{3}units

Step-by-step explanation:

using Pythagoras theorem

a^2+ b^2=c^2

a^2+ 3^2=(√21)^2

a^2+9= 21

a^2=21-9

a^2=12

a=√12

a=2√3

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A washer and a dryer cost $676 combined. The washer costs $74 less than the dryer. What is the cost of the dryer?
Arlecino [84]

Answer: The dryer cost $375.

Step-by-step explanation:

676 - 74 = 602

602/2 = 301

301 + 74 = 375

3 0
3 years ago
Help me to solve thisssss​
m_a_m_a [10]

Answer:

(a + 3)

Step-by-step explanation:

a³ - 9a = a(a² - 9) = a(a + 3)(a - 3)

a² + a - 6 = (a - 2)(a + 3)

a⁴ + 27a = a(a³ + 27) = a(a - 3)(a² + 6a + 9) = a(a - 3)(a + 3)(a + 3)

HCF = (a + 3)

Hope it helps.

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7 0
2 years ago
An engineer has designed a valve that will regulate water pressure on an automobile engine. The valve was tested on 180180 engin
tiny-mole [99]

Answer:

z=\frac{4.6-4.8}{\frac{0.9}{\sqrt{180}}}=-2.98    

p_v =P(Z  

If we compare the p value and the significance level given \alpha=0.1 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis,and we have enough evidence to conclude that the true mean is significantly lower thn 4.8 at 10% of signficance.  

Step-by-step explanation:

Data given and notation  

\bar X=4.6 represent the sample mean

\sigma=0.9 represent the population standard deviation

n=180 sample size  

\mu_o =4.8 represent the value that we want to test

\alpha=0.1 represent the significance level for the hypothesis test.

z would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if thetrue mean is below the specifications, the system of hypothesis would be:  

Null hypothesis:\mu \geq 4.8  

Alternative hypothesis:\mu < 4.8  

If we analyze the size for the sample is > 30 and we know the population deviation so is better apply a z test to compare the actual mean to the reference value, and the statistic is given by:  

z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}}  (1)  

z-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Calculate the statistic

We can replace in formula (1) the info given like this:  

z=\frac{4.6-4.8}{\frac{0.9}{\sqrt{180}}}=-2.98    

P-value

Since is a one sided test the p value would be:  

p_v =P(Z  

Conclusion  

If we compare the p value and the significance level given \alpha=0.1 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis,and we have enough evidence to conclude that the true mean is significantly lower thn 4.8 at 10% of signficance.  

4 0
3 years ago
At the souvenir shop. Theo buys k key chains and p photo frames
stealth61 [152]

Answer:

Total cost of Theo's purchases in terms of k and p=2.49(k + p) + 5.99

Step-by-step explanation:

Cost of k key chain=$2.49

Cost of p photo frames=$2.49

Cost of a T-shirt=$5.99

Total cost of all items=cost of k key chain + cost of p photo frame + cost of The shirt

=2.49k + 2.49p + 5.99

Factorise

2.49 is common to both k and p

=2.49(k + p) + 5.99

Total cost of Theo's purchases in terms of k and p=2.49(k + p) + 5.99

4 0
3 years ago
The fish population of Lake Collins is decreasing at a rate of 5% per year. In 2004 there were about 1,350 fish. Write an expone
ad-work [718]

Answer:

Part 1) The exponential function is equal to y=1,350(0.95)^{x}

Part 2) The population in 2010 was  992\ fish

Step-by-step explanation:

Part 1) Write an exponential decay function that models this situation

we know that

In this problem we have a exponential function of the form

y=a(b)^{x}

where

y ----> the fish population of Lake Collins since 2004

x ----> the time in years

a is the initial value

b is the base

we have

a=1,350\ fish

b=(100\%-5\%)=95\%=0.95

substitute

y=1,350(0.95)^{x} ----> exponential function that represent this scenario

Part 2) Find the population in 2010

we have

y=1,350(0.95)^{x}

so

For x=(2010-2004)=6\ years

substitute

y=1,350(0.95)^{6}=992\ fish

7 0
3 years ago
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