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adell [148]
3 years ago
6

F. If you make $28 dollars and hour and work for 32 hours in a week. How much money do you Gross ?

Mathematics
2 answers:
Kipish [7]3 years ago
5 0
627.2 this is the answer because 896 is the 100% and 89.6 is 10% of 896, that means multiply 89.6 with 7 and you get 627.2
Gala2k [10]3 years ago
3 0

Answer:

umm its$ 627.20

Step-by-step explanation:

all you do it divide 70/100 (896) you get a fraction turn it into a decimal.

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Use finite differences to identify the degree of the polynomial that best describes the data. 9 10 11 12 13 14
worty [1.4K]

The forward differences for this data is 1, 1, 1, 1, 1, 1 (since 10 - 9 = 1, 11 - 10 = 1, etc). Since we only need one iteration of differences, a linear polynomial will fit the data exactly.

4 0
2 years ago
Find the value of x. If necessary, write your answer in simplest radical form.<br> 12<br> 9
Kobotan [32]

Answer:

3√7

Step-by-step explanation:

9²+B²=12²

simplify

81+B²=144

minus the 81

B²= 63

3 0
2 years ago
Suppose that the sample standard deviation was s = 5.1. Compute a 98% confidence interval for μ, the mean time spent volunteerin
NISA [10]

Answer:

The 95% confidence interval would be given by (5.139;5.861)  

Step-by-step explanation:

1) Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X represent the sample mean for the sample  

\mu population mean (variable of interest)

s represent the sample standard deviation

n represent the sample size  

2) Confidence interval

Assuming that \bar X =5.5 and the ranfom sample n=1086.

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

In order to calculate the critical value t_{\alpha/2} we need to find first the degrees of freedom, given by:

df=n-1=1086-1=1085

Since the Confidence is 0.98 or 98%, the value of \alpha=0.02 and \alpha/2 =0.01, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.01,1085)".And we see that t_{\alpha/2}=2.33

Now we have everything in order to replace into formula (1):

5.5-2.33\frac{5.1}{\sqrt{1086}}=5.139    

5.5+2.333\frac{5.1}{\sqrt{1086}}=5.861

So on this case the 95% confidence interval would be given by (5.139;5.861)    We are 98% confident that the mean time spent volunteering for the population of parents of school-aged children is between these two values.

5 0
3 years ago
4x-2<br> x=5<br>can someone help me with this?​
kondaur [170]

Answer:

x= 5/2

Step-by-step explanation:

3 0
3 years ago
Dummy forgot his pin code. 20% of his pin code was 246.8 what was dummy pin code?
eduard
The dummies pin code would be 49.36.
8 0
3 years ago
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