Answer TCP/IP is the most common protocol in Local Area Networks.
Kaeya Should be the correct answer
// Variable to keep track of array size
int length = 0;
// Array itself
int array[] = {};
// while loop will take input in the array until a negative number is entered
while(input>=0){
stdin = new Scanner(System.in);
array[length] = stdin;
length +=1;
}
// int variable to terminate while loop
int i =0;
// keep track of index of output array
int y =0;
while(arr[i] != length){
// making output array
int output[]={}; bool flag;
// put the element in out put array considering if it the desired one
output[y] = array [i];
// Now check if it was the desired?
for(int z=1;z<=length;z++){
if(array[i+z]!=output[y]){
flag = true;
}
else
{
output[y]=0;
y+=1;
}
if(array[i+z+1]=output[y] && flag == true){
output[y] = array[i];
y+=1;
}
}
//output the array
for(int o=0;o<y;o++)
System.out.println(output[o];
<span>#include <iostream>
using namespace std;
bool bears(int n);
int main(){
int number;
do{
cout<<"enter the amount of bears (press 0 to stop the program): ";
cin>>number;
if (bears(number)){
cout<<"you have reached the goal!"<<endl;
}
else{
cout<<"sorry, you have not reached the goal."<<endl;
}
}while(number != 0);
}
bool bears(int n){
if (n < 42){
return false;
}
else if (n == 42){
return true;
}
else{
if (n % 5 == 0){
return bears(n - 42);
}
else if(n % 2 == 0){
return bears(n / 2);
}
else if(n % 4 == 0|| n % 3 == 0)
{
int one;
int two;
one=n%10;
two=(n%100)/10;
return bears(n - one * two);
}
}
<span>}</span></span>
Answer:
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