Answer:
The value of (f/g) (8) = -169
Step-by-step explanation:
<u>Step 1: explaining the question</u>
The quotient (f/g) is not defined at values of x ⇒ both the functions must be defined at a point for the combination to be defined.
⇒(f/g)(x) =(f(x)) / (g(x))
If f(x)= 3-2 and g(x)=1/x+5
⇒then according to the preceding formula: (f/g)(x) =(f(x)) / (g(x))
⇒(f/g)(8) = f(8) / g(8)
to solve this we have to find the value of both f(8) and g(8)
<u>Step 2: find value of f(8) and g(8)</u>
⇒ we know that f(x) = 3-2x and we know dat f(x) = f(8)
⇒ f(8) = 3-2(8)
f(8) = 3-16 = -13
⇒we know that g(x) = 1/x+5 and g(x) = g(8)
⇒ g(8) = 1/8+5
g(8) =1/13
These 2 equations we will insert in the following : ⇒(f/g)(8) = f(8) / g(8)
⇒ f/g (8) = -13 / (1/13) = -13 * 13/1 = -169
The value of (f/g) (8) = -169
The way to work out how much each person gets is to find out how much one part is worth.
We can do this by adding the ratio (1:2) which gives us 3.
Divide £120 by 3 parts and you get £40 as one part.
Because the ratio is one part : two parts, Matt gets £40 and Cat gets £80.
Answer:
y = 1/2 (2)x
Step-by-step explanation:
Using the equation y = abx , substitute both of your given points into that equation.
2 = ab2 and 4 = ab3 Solve each equation for a.
2⁄b2 and 4⁄b3 = a Therefore, 2⁄b2 = 4⁄b3
Cross multiply: 2b3 = 4b2 Divide both sides by b2
2b = 4 a = 2/4 = 1/2
b = 2
The required proof is given in the table below:
![\begin{tabular}{|p{4cm}|p{6cm}|} Statement & Reason \\ [1ex] 1. $\overline{BD}$ bisects $\angle ABC$ & 1. Given \\ 2. \angle DBC\cong\angle ABD & 2. De(finition of angle bisector \\ 3. $\overline{AE}$||$\overline{BD}$ & 3. Given \\ 4. \angle AEB\cong\angle DBC & 4. Corresponding angles \\ 5. \angle AEB\cong\angle ABD & 5. Transitive property of equality \\ 6. \angle ABD\cong\angle BAE & 6. Alternate angles \end{tabular}](https://tex.z-dn.net/?f=%20%5Cbegin%7Btabular%7D%7B%7Cp%7B4cm%7D%7Cp%7B6cm%7D%7C%7D%20%0A%20Statement%20%26%20Reason%20%5C%5C%20%5B1ex%5D%20%0A1.%20%24%5Coverline%7BBD%7D%24%20bisects%20%24%5Cangle%20ABC%24%20%26%201.%20Given%20%5C%5C%0A2.%20%5Cangle%20DBC%5Ccong%5Cangle%20ABD%20%26%202.%20De%28finition%20of%20angle%20bisector%20%5C%5C%20%0A3.%20%24%5Coverline%7BAE%7D%24%7C%7C%24%5Coverline%7BBD%7D%24%20%26%203.%20Given%20%5C%5C%20%0A4.%20%5Cangle%20AEB%5Ccong%5Cangle%20DBC%20%26%204.%20Corresponding%20angles%20%5C%5C%0A5.%20%5Cangle%20AEB%5Ccong%5Cangle%20ABD%20%26%205.%20Transitive%20property%20of%20equality%20%5C%5C%20%0A6.%20%5Cangle%20ABD%5Ccong%5Cangle%20BAE%20%26%206.%20Alternate%20angles%0A%5Cend%7Btabular%7D)