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2 years ago

Please anyone can you help me I'm confused

Mathematics

1 answer:

Zarrin [17]2 years ago

7 0

Answer:

Your Answer Would be C

Step-by-step explanation:

Look At Graph C when we go to the "Model Size" And Find 2 The Line Is Midway to the 2 on "Statue Size" and half of 2 is 1 so C Is Correct

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Write 9.55 as a mixed number

jeka57 [31]

9.55 as a mixed number would be 9 11/20.

9.55 = 9 55/100 = 9 11/20

Hope this helps !

7 0

2 years ago

A number is not an integer what type of number can it be

MrRa [10]

It can be a decimal or fraction. An integer HAS to be a whole number.
-2, 10, and 4300 are integers
8.4, -0.14568, and 1/2 are not integers

8 0

3 years ago

Read 2 more answers

Quadratic equations and complex numbers PLEASE HELPPPP ASAP

kondor19780726 [428]

we are given

$27x^3-1=0$

we can also write it as

$(3x)^3-(1)^3=0$

now, we can use factor formula

$a^3-b^3=(a-b)(a^2+ab+b^2)$

we can use above formula

we get

$(3x)^3-(1)^3=(3x-1)((3x)^2+3x\times 1+(1)^2)$

now, we can simplify it

$27x^3-1=(3x-1)(9x^2+3x+1)$

now, we can set it to 0

$27x^3-1=(3x-1)(9x^2+3x+1)=0$

and then we can solve for x

$(3x-1)(9x^2+3x+1)=0$

$3x-1=0$

$x=\frac{1}{3}$

$9x^2+3x+1=0$

now, we can use quadratic formula

$x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

now, we can plug values

and we get

$x=\frac{-3\pm \sqrt{3^2-4\cdot \:9\cdot \:1}}{2\cdot \:9}$

$x=-\frac{1}{6}+i\frac{\sqrt{3}}{6},\:x=-\frac{1}{6}-i\frac{\sqrt{3}}{6}$

So, we will get solution as

$x=\frac{1}{3},\:x=-\frac{1}{6}+i\frac{\sqrt{3}}{6},\:x=-\frac{1}{6}-i\frac{\sqrt{3}}{6}$ ...............Answer

5 0

3 years ago

HELP ASAP LIKE RNNNN

Ne4ueva [31]

Answer:

(x,y)--->(x-5,y-3) so that is your abswer

4 0

2 years ago

What is the percent of 2 = 1.84?

beks73 [17]

1.84 is 92% of 2.

Not sure if this is what you were going for, but I'm pretty sure you are. Let me know if not!

4 0

3 years ago