Simplifying Rs = st + -1Rt Solving sR = st + -1tR Solving for variable 's'. Move all terms containing s to the left, all other terms to the right. Add '-1st' to each side of the equation. sR + -1st = st + -1st + -1tR Combine like terms: st + -1st = 0 sR + -1st = 0 + -1tR sR + -1st = -1tR Combine like terms: -1tR + tR = 0 sR + -1st + tR = 0
Answer:
95% confidence interval for the difference between the average mass of eggs in small and large nest is between a lower limit of 0.81 and an upper limit of 2.39.
Step-by-step explanation:
Confidence interval is given by mean +/- margin of error (E)
Eggs from small nest
Sample size (n1) = 60
Mean = 37.2
Sample variance = 24.7
Eggs from large nest
Sample size (n2) = 159
Mean = 35.6
Sample variance = 39
Pooled variance = [(60-1)24.7 + (159-1)39] ÷ (60+159-2) = 7619.3 ÷ 217 = 35.11
Standard deviation = sqrt(pooled variance) = sqrt(35.11) = 5.93
Difference in mean = 37.2 - 35.6 = 1.6
Degree of freedom = n1+n2 - 2 = 60+159-2 = 217
Confidence level = 95%
Critical value (t) corresponding to 217 degrees of freedom and 95% confidence level is 1.97132
E = t×sd/√(n1+n2) = 1.97132×5.93/√219 = 0.79
Lower limit = mean - E = 1.6 - 0.79 = 0.81
Upper limit = mean + E = 1.6 + 0.79 = 2.39
95% confidence interval for the difference in average mass is (0.81, 2.39)
Well 5=5
and 37/40
hmm, try to get that 40 into an nice number that is multiplule of 10
if we divide top and bottom by 4 that would work
9.25/10=92.5=100=925/1000=925 thousandths=0.925
so the decimal would be 5.925
Answer:
j/k + 6
Step-by-step explanation:
Add 6 to the quotient of j and k comes out to:
j/k + 6
