Answer:
-2.167
Step-by-step explanation:
6X = 2-15
6X = -13
X= -13 / 6
Answer: 0.03855
Step-by-step explanation:
Given :A population of skiers has a distribution of weights with mean 190 pounds and standard deviation 40 pounds.
Its maximum safe load is 10000 pounds.
Let X denotes the weight of 50 people.
As per given ,
Population mean weight of 50 people =
Standard deviation of 50 people 
Then , the probability its maximum safe load will be exceeded =
![P(X>10000)=P(\dfrac{X-\mu}{\sigma}>\dfrac{10000-9500}{282.84})\\\\=P(z>1.7671-8)\\\\=1-P(z\leq1.7678)\ \ \ \ [\because\ P(Z>z)=P(Z\leq z)]\\\\=1-0.96145\ \ \ [\text{ By p-value of table}]\\\\=0.03855](https://tex.z-dn.net/?f=P%28X%3E10000%29%3DP%28%5Cdfrac%7BX-%5Cmu%7D%7B%5Csigma%7D%3E%5Cdfrac%7B10000-9500%7D%7B282.84%7D%29%5C%5C%5C%5C%3DP%28z%3E1.7671-8%29%5C%5C%5C%5C%3D1-P%28z%5Cleq1.7678%29%5C%20%5C%20%5C%20%5C%20%5B%5Cbecause%5C%20P%28Z%3Ez%29%3DP%28Z%5Cleq%20z%29%5D%5C%5C%5C%5C%3D1-0.96145%5C%20%5C%20%5C%20%5B%5Ctext%7B%20By%20p-value%20of%20table%7D%5D%5C%5C%5C%5C%3D0.03855)
Thus , the probability its maximum safe load will be exceeded = 0.03855
Answer: 49
reason:
okay so basically to get to 3 to 5 you have to add 2. To get to 21 to 35 you need to add 14. To get to 5 to 7 you need to add 2, therefore adding 14 to 35. It's a pattern :)
Answer:
The diameter is 13.88 feet.
Step-by-step explanation:
1. The formula for calculate the volume of a sphere is:

Where
is the radius.
2. The diameter is:

3. So, you must solve for the radius in the first equation:
![r=\sqrt[3]{\frac{4(790.272ft^{3} )}{3\pi}}\\r=6.94ft](https://tex.z-dn.net/?f=r%3D%5Csqrt%5B3%5D%7B%5Cfrac%7B4%28790.272ft%5E%7B3%7D%20%29%7D%7B3%5Cpi%7D%7D%5C%5Cr%3D6.94ft)
4. Then, the diameter is:

Find two numbers that multiply to -30 (last term) and add to 7 (middle coefficient)
The two numbers are 10 and -3
10 times -3 = -30
10 plus -3 = 7
Using those two values gets us the two factors (y+10) and (y-3)
Therefore, y^2+7y-30 factors to (y+10)(y-3)
The equation y^2+7y-30 = (y+10)(y-3) is true for all values of y.