Answer:
We conclude that the equation in slope-intercept form of the line that passes through (12,9) and is perpendicular to the graph of y = -3/4x + 1 will be:
Step-by-step explanation:
We know the slope-intercept form of the line equation
y = mx+b
where
Given the line
y = -3/4x + 1
comparing with the slope-intercept form of the line equation
The slope = m = -3/4
We know that a line perpendicular to another line contains a slope that is the negative reciprocal of the slope of the other line, such as:
slope = m = -3/4
Thus, the slope of the new perpendicular line = – 1/(-3/4) = 4/3
Using the point-slope form

where m is the slope of the line and (x₁, y₁) is the point
substituting the values of the slope = 4/3 and the point (12, 9)


Add 9 to both sides



Therefore, we conclude that the equation in slope-intercept form of the line that passes through (12,9) and is perpendicular to the graph of y = -3/4x + 1 will be:
What are the clues fvfrce
Answer: Irrational
Step-by-step explanation:
Answer:
We conclude that the total amount accrued, principal plus interest, from compound interest on an original principal of $2500 at a rate of 5% per year compounded 6 times per year over 8 years is $3723.38.
Step-by-step explanation:
Given
Principle P = $2500
Interest rate r = 5% = 0.05
Time period t = 8 years
To determine
Accrue Amount A = ?
Using the compound interest equation

where:
A represents the Accrue Amount
P represents the Principal Amount
r represents the interest rate
t represents the time period in years
n represents the number of compounding periods per unit t
Important tip:
- Given that the interest is compounded 6 times each year, therefore, the value of n = 6.
now substituting P = 2500, r = 0.05, t = 8 and n = 6 in the equation



∵ 
$
Therefore, we conclude that the total amount accrued, principal plus interest, from compound interest on an original principal of $2500 at a rate of 5% per year compounded 6 times per year over 8 years is $3723.38.
Answer:
B
Step-by-step explanation:
7mn³|7m²n³ ---14mn^5
| m---2n²
LCM=7mn³×m×2n²
=14m²n^5
or LCM of 7,14 =14
Highest power of m=2
Highest power of n=5
LCM=14m²n^5