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QveST [7]
3 years ago
10

HELP HELPPPP PLEASEE

Mathematics
2 answers:
horrorfan [7]3 years ago
7 0

Answer:

a

Step-by-step explanation:

maks197457 [2]3 years ago
5 0

Answer:

f(n)=o.15n. is you answer

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What is the measure of angle WZX?
Aleksandr [31]
I hate Time4Learning. I took that back in middle school.

Here's how these expressions work together. First, you need to remember WZY is a right angle (90 degrees). Now, keep that in mind when we add both equation.

3c + 2c + 2 - 7 = 90

5c - 5 = 90

5c - 5 + 5 = 90 + 5

5c = 95

5c/5 = 95/5

c = 19. Now, put 19 in the place of c and solve.

3(19) + 2 = 57 + 2 =

59 degrees.

The measurement of angle WZX is equal to 59 degrees, B.
8 0
3 years ago
HELP ME PLEASE I APPRECIATE IT
Molodets [167]
1 is m=n/x
2 is 15 rows
5 0
4 years ago
Can somebody please help me
guajiro [1.7K]

Here is your answer

B. (12,30)

REASON:

Given,

y= 2x+6 .......(i)

3x-y= 6 .......(ii)

Putting the value of y from eq.i in eq.ii we get

3x-(2x+6)=6

3x-2x-6=6

=6+6

x=12

Putting x=12 in eq.i we get

y= 2x+6

y= 2×12+6

y= 24+6

y= 30

So,

\bold{x=12 and y= 30}

Hence answer is (12,30) in which x=12 and y=30

HOPE IT IS USEFUL

5 0
3 years ago
What rational number equals 0.1111111111
Katen [24]

Answer:

1/9

Step-by-step explanation:

1/9 is a fraction, so it is rational.

6 0
3 years ago
Read 2 more answers
AM is a median in △ABC (M∈ BC ). A line drawn through point M intersects AB at its midpoint P. Find areas of △APC and △PMC, if A
Snowcat [4.5K]

Answer:

The area of APC is 70m². The area of triangle PMC is 35m².

Step-by-step explanation:

Let the area of triangle ABC be x.

It is given that AM is median, it means AM divides the area of triangle in two equal parts.

\text{Area of }\triangle ACM=\text{Area of }\triangle ABM=\frac{x}{2}    .....(1)

The point P is the midpoint of AB, therefore the area of APC and BPC are equal.

\text{Area of }\triangle APC=\text{Area of }\triangle BPC=\frac{x}{2}          ......(2)

The point P is midpoint of AB therefore the line PM divide the area of triangle ABM in two equal parts. The area of triangle APM and BPM are equal.

\text{Area of }\triangle APM=\text{Area of }\triangle BPM=\frac{x}{4}        .....(3)

The area of triangle APM is 35m².

\text{Area of }\triangle APM=\frac{x}{4}

35=\frac{x}{4}

x=140

Therefore the area of triangle ABC is 140m².

Using equation (2).

\text{Area of }\triangle APC=\frac{x}{2}

\text{Area of }\triangle APC=\frac{140}{2}

\text{Area of }\triangle APC=70

Therefore the area of triangle APC is 70m².

Using equation (3), we can say that the area of triangle BPM is 35m² and by using equation (2), we can say that the area of triangle BPC is 70m².

\triangle BPC=\triangle BPM+\triangle PMC

70=35+\triangle PMC

35=\triangle PMC

Therefore the area of triangle PMC is 35m².

8 0
4 years ago
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