We must mix 240 liters of the 51 % solution and 10 liters of the 26 % solutions to produce 250 liters of 50 % solution.
<h3>How to prepare a solution by using weighted averages</h3>
Herein we have to prepare a solution with fertilizers by mixing two <em>different</em> solutions. The amount needed of the 51 % solution can be found by weighted averages:
(50/100) · (250 L) = (51/100) · x + (26/100) · (250 - x)
50 · 250 = 51 · x + 26 · 250 - 26 · x
24 · 250 = 25 · x
x = 240
We must mix 240 liters of the 51 % solution and 10 liters of the 26 % solutions to produce 250 liters of 50 % solution.
To learn more on weighted averages: brainly.com/question/18554478
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Answer:
4+9= 13
Step-by-step explanation:
Answer:
4 1/12
Step-by-step explanation:
2 1/3 x 1 3/4 = 7/3 x 7/4 = 49/12 = 4 1/12
Answer:
66 HR
Step-by-step explanation:
We can set up an equivalent proportion and cross-multiply like this:
22/7=x/21
Cross multiply.
7x=462
Divide by 7 on both sides.
x=66
HTH :)
Yes, the equation is balanced. (brainliest?)