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Oksanka [162]
2 years ago
13

A point plotted at 30.05 on a number line which of these describes the location of the point

Mathematics
1 answer:
Solnce55 [7]2 years ago
8 0

Answer:

Between 30 and 31

Step-by-step explanation:

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Given 36 − 9, simplify the expression using the Difference of Squares.
lisov135 [29]

Answer:

See below

Step-by-step explanation:

Using formula

  • x^2 - y^2 = (x + y)(x - y)

Applying to given expression

  • 36 - 9 =
  • 6^2 - 3^2=
  • (6 + 3)(6 - 3)=
  • 9*3=
  • 27
6 0
2 years ago
2x-2y=22 find the value of y when x equals 2
11111nata11111 [884]

Answer:

y = -9

Step-by-step explanation:

Step 1: Substitute x

2(2) - 2y = 22

Step 2: Isolate y

-2y = 18

Step 3: Divide by -2

y = -9

And you have your final answer!

8 0
3 years ago
Read 2 more answers
The producer of a certain bottling equipment claims that the variance of all its filled bottles is .027 or less. A sample of 30
o-na [289]

Answer:

p_v = P(\chi^2_{29}>42.963)=1-0.954=0.0459

b. between .025 and .05

Step-by-step explanation:

Previous concepts and notation

The chi-square test is used to check if the standard deviation of a population is equal to a specified value. We can conduct the test "two-sided test or a one-sided test".

\bar X represent the sample mean

n = 30 sample size

s= 0.2 represent the sample deviation

\sigma_o =\sqrt{0.027}=0.164 the value that we want to test

p_v represent the p value for the test

t represent the statistic

\alpha= significance level

State the null and alternative hypothesis

On this case we want to check if the population standard deviation is less than 0.027, so the system of hypothesis are:

H0: \sigma \leq 0.027

H1: \sigma >0.027

In order to check the hypothesis we need to calculate the statistic given by the following formula:

t=(n-1) [\frac{s}{\sigma_o}]^2

This statistic have a Chi Square distribution distribution with n-1 degrees of freedom.

What is the value of your test statistic?

Now we have everything to replace into the formula for the statistic and we got:

t=(30-1) [\frac{0.2}{0.164}]^2 =42.963

What is the approximate p-value of the test?

The degrees of freedom are given by:

df=n-1= 30-1=29

For this case since we have a right tailed test the p value is given by:

p_v = P(\chi^2_{29}>42.963)=1-0.954=0.0459

And the best option would be:

b. between .025 and .05

6 0
3 years ago
Find the Volume. Plz Help
koban [17]

Answer:

B

Step-by-step explanation:

V = \frac{l*w*h}{2} = \frac{18*12*9}{2} = \frac{1944}{2} = 972

3 0
3 years ago
Read 2 more answers
What is the solution to the equation <br><br> 7(3-x)=-7(x+3)-4
marissa [1.9K]

Answer:

No solution

Step-by-step explanation:

21−7x=−7x−21−4

21−7x=−7x−25

21=−25

No solution

4 0
3 years ago
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