Log(4k - 5) = log(2k - 1)
log(4k) - log(5) = log(2k) - log(1)
0.6020599913k - 0.6989700043 = 0.3010299957k - 0
0.6020599913k - 0.6989700043 = 0.3010299957k
<u>-0.6020599913k -0.6020599913k</u>
<u>-0.6989700043</u> = <u>-0.3010299957k</u>
-0.3010299957 -0.3010299957
2.321928094 = k
Answer:
no it is not
Step-by-step explanation:
-5, and 7
Are you sure about your solves??
I think correct answer is 6,
I don't know but the standard way is in the photo:
<span>Let time taken by Luke to cover the distance = x hours
Speed of Luke = 6 miles per hour
Therefore, Distance covered by Luke = 6x ------(1)
Speed of Micah = 4 miles per hour
Since Micah walked 2 miles before Luke started running, Luke started 1/2 an hour after Micah started.
Therefore time taken by Micah to cover the distance = x+1/2
Distance covered by Micah = 4(x + 1/2) -------(2)
Equating (1) and (2)
6x = 4(x+1/2)
6x = 4x +2
2x = 2
x= 1
Therefore Luke would take 1 hour to cover the distance covered by Micah.</span>
