Help me out (geometry)

Mathematics

1 answer:

VLD [36.1K]2 years ago

5 0

Answer:

⊥

Step-by-step explanation:

d and b meet at a 90 degree angle ( as shown by the box)

The lines are perpendicular (⊥)

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Identify the factors of x2-8x-20

sukhopar [10]

Simplifying x2 + -8x = 20 Reorder the terms: -8x + x2 = 20 Solving -8x + x2 = 20 Solving for variable 'x'. Reorder the terms: -20 + -8x + x2 = 20 + -20 Combine like terms: 20 + -20 = 0 -20 + -8x + x2 = 0 Factor a trinomial. (-2 + -1x)(10 + -1x) = 0 Subproblem 1Set the factor '(-2 + -1x)' equal to zero and attempt to solve: Simplifying -2 + -1x = 0 Solving -2 + -1x = 0 Move all terms containing x to the left, all other terms to the right. Add '2' to each side of the equation. -2 + 2 + -1x = 0 + 2 Combine like terms: -2 + 2 = 0 0 + -1x = 0 + 2 -1x = 0 + 2 Combine like terms: 0 + 2 = 2 -1x = 2 Divide each side by '-1'. x = -2 Simplifying x = -2 Subproblem 2Set the factor '(10 + -1x)' equal to zero and attempt to solve: Simplifying 10 + -1x = 0 Solving 10 + -1x = 0 Move all terms containing x to the left, all other terms to the right. Add '-10' to each side of the equation. 10 + -10 + -1x = 0 + -10 Combine like terms: 10 + -10 = 0 0 + -1x = 0 + -10 -1x = 0 + -10 Combine like terms: 0 + -10 = -10 -1x = -10 Divide each side by '-1'. x = 10 Simplifying x = 10Solutionx = {-2, 10}

6 0

2 years ago

Read 2 more answers

the mgf of a random variable x is e^3(e^t-1). Find P[mean - standard deviation squared < X < 1/2( mean + standard deviatio

postnew [5]

The given MGF is that for a random variable following a Poisson distribution with parameter $\lambda=3$ .

This means $\mathbb E(X)=\mathbb V(X)=\lambda$ , and $X$ has PMF

$f_X(x)=\begin{cases}\dfrac{3^xe^{-3}}{x!}&\text{for }x\ge0\\0&\text{otherwise}\end{cases}$

So, the desired probability is

$\mathbb P\left(\lambda-\lambda^2$

This is equivalent to

$\displaystyle\sum_{x=0}^2\mathbb P(X=x)=\sum_{x=0}^2\frac{3^x}{x!e^3}=\frac{17}{2e^3}\approx0.4232$