Answer:
is an electric force on the potassium ion due to the chloride ion.
Explanation:
Charge on potassium ion =
Charge on chlorine ion =
Separation between these two charges = r =
Electric force on the potassium ion due to the chloride ion = F
Coulomb's law is given as ;
= Charges on both charges
r = distance between the charges
K = Coulomb constant =
(negative sign indicates that attractive force is exerting between two ions)
is an electric force on the potassium ion due to the chloride ion.
at equilibrium.
<h3>Explanation</h3>
Concentration for each of the species:
There was no Y to start with; its concentration could only have increased. Let the change in be .
Make a table.
Two moles of X will be produced and two moles of Z consumed for every one mole of Y produced. As a result, the <em>change</em> in will be and the <em>change</em> in will be .
.
Add the value in the C row to the I row:
.
What's the equation of for this reaction? Raise the concentration of each species to its coefficient. Products go to the numerator and reactants are on the denominator.
.
. As a result,
.
.
The degree of this polynomial is three. Plot the equation on a graph and look for any zeros. There's only one zero at . All three concentrations end up greater than zero.
Hence the equilibrium concentration of Y: .
Answer:
B. Hypothesis
Explanation: A hypothesis is a guess of what will or might happen before an experiment.
Can you give use an clue of what it is all about
Answer: In a half-cell is where occurs the either oxidation (loss of electrons) or reduction (gain of electrons) but not both.
Explanation:
1) In an electrolitic cell you can identify two half-cells.
2) In one half-cell occurs the oxidation
3) In the other half-cell occurs the reduction.
4) The half-cell where oxidation occurs is the anode.
In the anode the spieces increase its oxidation number, which is what oxidation means. Increasing the oxidation number means that the spieces is losing electrons.
5) The half-cell where reduction occurs is the cathode.
Reduction is the reduction of the oxidation number and this occurs due to the gain of electrons.