Hydrolysis of Acetal is shown below, this reaction is carried out in acidic medium. In this reaction
Hemiacetal is formed after partial hydrolysis and on completion of reaction hemiacetal is converted into
Aldehyde. Also, two moles of
Alcohol is produced per molecule of acetal.
Reaction mechanism is as below,
1. color of the rock
2. shape of the rock
3. how the rock is formed
4. who discovered the rock
that is it
This problem is providing a reaction whereby nitrogen dioxide is produced from nitrogen monoxide and oxygen. Given the rate law, we are asked to quantify the increase in the rate when the concentration of oxygen is tripled. At the end, the result turns out to be an increase by a factor of 3 as well.
<h3>Chemical kinetics:</h3>
In chemistry, chemical kinetics is a tool for us to quantify increases or decreases (among others) in the rate of a chemical reaction, when the concentration or even temperature are manipulated. In such a way, with this reaction's rate law:
![rate=k[O_2][NO]^2](https://tex.z-dn.net/?f=rate%3Dk%5BO_2%5D%5BNO%5D%5E2)
One can see it is first-order with respect to oxygen and second-order with respect to nitrogen monoxide. Now, since the concentration of oxygen is tripled, we can setup an r2 to r1 ratio, being the former the reaction after the increase in the oxygen's concentration and the former the initial one:
![\frac{r2}{r1} =\frac{k_2[O_2]_2[NO]^2_2}{k_1[O_2]_1[NO]^2_1}](https://tex.z-dn.net/?f=%5Cfrac%7Br2%7D%7Br1%7D%20%3D%5Cfrac%7Bk_2%5BO_2%5D_2%5BNO%5D%5E2_2%7D%7Bk_1%5BO_2%5D_1%5BNO%5D%5E2_1%7D)
Thus, since the both of the rate constants are the same as no temperature change is pointed out, and the concentration of nitrogen monoxide is not said to have changed, we can cancel them out:
![\frac{r2}{r1} =\frac{[O_2]_2}{[O_2]_1}](https://tex.z-dn.net/?f=%5Cfrac%7Br2%7D%7Br1%7D%20%3D%5Cfrac%7B%5BO_2%5D_2%7D%7B%5BO_2%5D_1%7D)
Hence, we plug in the given increase (tripling):
![\frac{r2}{r1} =\frac{3*[O_2]_1}{[O_2]_1}\\\\\frac{r2}{r1} =3](https://tex.z-dn.net/?f=%5Cfrac%7Br2%7D%7Br1%7D%20%3D%5Cfrac%7B3%2A%5BO_2%5D_1%7D%7B%5BO_2%5D_1%7D%5C%5C%5C%5C%5Cfrac%7Br2%7D%7Br1%7D%20%3D3)
Therefore the increase is done by a factor of 3, which makes sense because the reaction is first-order with respect to oxygen.
Learn more about rate laws: brainly.com/question/13309369
Answer:
383.90K
Explanation:
P1 = 851mmHg
T1 = 330K
T2 = ?
P2 = 990mmHg
To solve for P2, we have to use pressure law which states that the pressure of a fixed mass of fixed is directly proportional to its temperature provided that volume remains constant
Mathematically,
P = kT, k = P/T
P1 / T1 = P2 / T2 = P3 / T3 =.......=Pn / Tn
P1 / T1 = P2 / T2
T2 = (P2 × T1) / P1
T2 = (990 × 330) / 851
T2 = 383.90K
The final temperature of the gas is 383.90K
Explanation:
1 ) Temperature of Venus in Kelvins = 757 Kelvins

Temperature of Venus in degrees Celsius =
2 ) Temperature on Mercury at night = 


Temperature on Mercury at night in degree Celsius = 167.22° C