m₁ = mass hanged initially = 0.2 kg
x₁ = initial stretch in the spring = 8 cm = 0.08 m
k = spring constant of the spring
the weight of the mass hanged is balanced by the spring force by the spring hence
Spring force = weight of mass hanged
k x₁ = m₁ g
k (0.08) = (0.2) (9.8)
k = 24.5 N/m
m₂ = mass hanged later = 0.5 kg
x₂ = final stretch in the spring = ?
k = spring constant of the spring = 24.5 N/m
the weight of the mass hanged is balanced by the spring force by the spring hence
Spring force = weight of mass hanged
k x₂ = m₂ g
(24.5) x₂ = (0.5) (9.8)
x₂ = 0.2 m = 20 cm
The frequency of the data set that matches with the interval stated are:
50 - 54: 2
55 - 59: 6
60 - 64: 7
65 - 69: 3
70 - 74: 2
<h3>What is a Frequency?</h3>
Frequency is the number of times a data point or a set of points within an interval appears often in a data set.
The corresponding frequency to each of the interval given for the data would be as follows:
50 - 54: 2
55 - 59: 6
60 - 64: 7
65 - 69: 3
70 - 74: 2
Learn more about the frequency of a data on:
brainly.com/question/15422753
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Answer:
11/3
Step-by-step explanation:
m=(y2-y1)/(x2-x1)
m=(55-22)/(15-6)
m=33/9
simplify
m=11/3
Answer:
0.0406, 0.8284,0.7887
Step-by-step explanation:
Given that Mattel Corporation produces a remote-controlled car that requires three AA batteries
X is N(34, 5.5)
Hence sample size of 25 would follow a t distribution with df = 24
This is because sample size <30
t distribution with df 24 would be bell shaped symmetrical about the mean and unimodal.
Std error of sample mean = std dev /sqrt n=
Prob (X>36) = 
i.e nearly 4.1% of the sample would have a mean useful life of more than 36 hours
X>33.5 implies 
=0.82837
=0.8284 proportion will have a mean useful life greater than 33.5 hours
Proportion between 33.5 and 36 hours
= 
The answer is C, because your homework assignments (h) is equal to 8 (Amount of assignments in one week) times the number of weeks.
