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2 years ago

Simplify the expression 6h+(−7.9d)−16+5d−3.3h.

Mathematics

2 answers:

alina1380 [7]2 years ago

8 0

-2.9d-16-3.3h pemdas

iVinArrow [24]2 years ago

5 0

Answer:

2.7h-2.9d-16

Step-by-step explanation:

The first thing you need to do is combine like terms.

So, given 6h+(-7.9d)-16+5d-3.3h

-7.9d can combine with 5d, and 6h can combine with -3.3h.

-7.9d+5d=-2.9d

6h-3.3h=2.7h

Now all you have left is the -16 which has nothing to be combined with. Therefore, giving you the answer 2.7h-2.9d-16.

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Brilliant_brown [7]

Answer:I got 18.28

Step-by-step explanation:

so for getting the perimeter, you only need the outer line, so you sum the measurements you have for the rectangle: 1+2+2+7= 12. After that you need the circumference of the circle, you can figure it out by using the formula C = 2pi(r) You can find the radius by substracting the known sides of the rectangle attached to the circle from the bottom base and then dividing it in 2, leaving us with a radius of 2. Then we input values; C=2pi(2) which equals 4pi, but we need to divide that in half since it’s only half a circle. That leaves us with 2pi, or 6.28. Then we add the perimeter of the square, which was 12, and 6.28+12= 18.28

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2 years ago

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Step-by-step explanation:

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3 years ago

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Step-by-step explanation:

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3 years ago

I NEED HELP PLEASE ASAP !

In-s [12.5K]

The first rule you need to know is

$(a^b)^c=a^{bc}$

So, you have

$\dfrac{(x^{25})^{-6}}{(x^{-3})^{48}}=\dfrac{x^{25\cdot(-6)}}{x^{-3\cdot 48}}=\dfrac{x^{-150}}{x^{-144}}$

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3 years ago

Read 2 more answers

For positive acute angles A and B, it is known that cos A= 20/29 and tan B= 11/60. Find the value of cos(A + B) in simplest form

jek_recluse [69]

Answer:

$\displaystyle \cos(A + B) =\frac{969}{1769}$

Step-by-step explanation:

We are given that:

$\displaystyle \cos A=\frac{20}{29}\text{ and } \tan B=\frac{11}{60}$

Where A and B are positive acute angles.

And we want to find cos(A + B).

Recall that cosine is the ratio of the adjacent side to the hypotenuse. Using this information, find the opposite side with respect to Angle A:

$o=\sqrt{29^2-20^2}=21$

Tangent is the ratio of the opposite side to the adjacent side. Find the hypotenuse with respect to Angle B:

$h=\sqrt{11^2+60^2}=61$

In summary:

With respect to Angle A, the adjacent side is 20, opposite is 21, and the hypotenuse is 29.

With respect to Angle B, the adjacent side is 60, the opposite is 11, and the hypotenuse is 61.

We can rewrite our expression as:

$\displaystyle \cos(A+B)=\cos A\cos B-\sin A\sin B$

Using the above information, substitute in the appropriate values. Note that since A and B are positive acute angles, all trigonometric values will be positive. Hence:

$\displaystyle \cos(A + B)=\left(\frac{20}{29}\right)\left(\frac{60}{61}\right)-\left(\frac{21}{29}\right)\left(\frac{11}{61}\right)$

Simplify:

$\displaystyle \cos(A + B) =\frac{1200-231}{1769}=\frac{969}{1769}$

3 0

3 years ago

Simplify the expression 6h+​(−7.9d​)−16+5d−3.3h.

Simplify the expression 6h+(−7.9d)−16+5d−3.3h.