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Nuetrik [128]
3 years ago
6

What is the pH of a 4.0 x 10-10 M HCl solution?

Chemistry
1 answer:
Svet_ta [14]3 years ago
7 0

Answer: pH = 9.40

Explanation:  pH = - log[H3O^+] .

 HCl reacts with water : HCl + H2O ->  Cl^- + H3O^+

So [H3O^+] = c(HCl) = 4.0· 10^-10 M

pH = - log(4.0· 10^-10 M) = 9.398

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The given balanced chemical reaction is,

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Now we have to calculate the molarity of I_3^-.

\text{Molarity of }I_3^-=\frac{\text{Moles of }I_3^-}{\text{Volume of solution}}

Now put all the given values in this formula, we get:

\text{Molarity of }I_3^-=\frac{0.003848mole}{0.03L}=0.128mole/L=0.128M

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