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3 years ago

11

Which of these elements has an electron dot

1 answer:

Arada [10]3 years ago

6 0

Answer:

i think is o helium, He........

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What specifically determines how much energy is available in a molecular

HACTEHA [7]

C The number and types of bonds within the molecule.

Explanation:

In a molecule, the number and types of bonds present determines the amount of available energy therein.

When bonds are broken or formed, energy is usually released.

Elements combine with one another in order to attain stability in this state.
Through this process, they form bonds by attraction.
Where atoms exchange their valence electrons by losing or gaining it, electrovalent bonds form.
In covalent molecules, electrons are usually shared between atoms.
An attraction result from this type of interaction.
The bond formed stores energy in the process.
When bonds are broken, energy is usually released. The energy accrues when the bond was being formed.
In molecules, we have covalent bond.

Learn more:

Bond brainly.com/question/7213980

Covalent bonds brainly.com/question/5258547

#learnwithBrainly

4 0

3 years ago

Please help!!!!!! Name 3 differences between vascular and non vascular plants

Arlecino [84]

Am letting the picture doing the talk.

8 0

3 years ago

Who were good friends in one day a stranger came<br><br>

insens350 [35]

Answer:

???

Explanation:

5 0

3 years ago

Be sure to answer all parts. Consider the formation of ammonia in two experiments. (a) To a 1.00−L container at 727°C, 1.30 mol

Sonbull [250]

<u>Answer:</u> The value of $K_c$ for $2NH_3(g)\rightleftharpoons N_2(g)+3H_2(g)$ reaction is $5.13\times 10^2$

<u>Explanation:</u>

We are given:

Initial moles of nitrogen gas = 1.30 moles

Initial moles of hydrogen gas = 1.65 moles

Equilibrium moles of ammonia = 0.100 moles

Volume of the container = 1.00 L

For the given chemical equation:

$N_2(g)+3H_2(g)\rightleftharpoons 2NH_3(g)$

<u>Initial:</u> 1.30 1.65

<u>At eqllm:</u> 1.30-x 1.65-3x 2x

Evaluating the value of 'x'

$\Rightarrow 2x=0.100\\\\\Rightarrow x=0.050mol$

The expression of $K_c$ for above equation follows:

$K_c=\frac{[NH_3]^2}{[N_2]\times [H_2]^3}$

Equilibrium moles of nitrogen gas = $(1.30-x)=(1.30-0.05)=1.25mol$

Equilibrium moles of hydrogen gas = $(1.65-x)=(1.65-0.05)=1.60mol$

Putting values in above expression, we get:

$K_c=\frac{(0.100)^2}{1.25\times (1.60)^3}\\\\K_c=1.95\times 10^{-3}$

Calculating the $K_c'$ for the given chemical equation:

$2NH_3(g)\rightleftharpoons N_2(g)+3H_2(g)$

$K_c'=\frac{1}{K_c}\\\\K_c'=\frac{1}{1.95\times 10^{-3}}=5.13\times 10^2$

Hence, the value of $K_c$ for $2NH_3(g)\rightleftharpoons N_2(g)+3H_2(g)$ reaction is $5.13\times 10^2$

8 0

3 years ago

Read 2 more answers

How did oxygen first enter Earth's atmosphere?

forsale [732]

Answer:

I think c biological processes

8 0

2 years ago