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vodomira [7]
3 years ago
10

1. The effect of a catalyst on a chemical reaction is to

Chemistry
2 answers:
Sonja [21]3 years ago
7 0

Answer: c?

Explanation:

NemiM [27]3 years ago
6 0

Answer:

the catalyst is for activation energy

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If sulfur dioxide and oxygen can be made into sulfur trioxide, what is the reverse reaction? A. SO3 +O2à SO3 B. 2SO2 + O2à 2SO3
ycow [4]
REVERSE REACTION WILL BE SO2+O2
7 0
3 years ago
Read 2 more answers
What is the ph of an aqueous solution with the hydronium ion concentration : [h3o+] = 3 x 10-5 m ?
BaLLatris [955]

The concentration of hydrogen can be shown as:

[H+ ] = 3 * 10-5 M

pH can be determined as:

pH = - log [H+ ]

= - log (3 * 10-5)

= 4.53

Thus the pH of solution is 4.53


8 0
3 years ago
When one mole of a solute is present in 500 cm3 of solution, then the concentration of the solution is:
Schach [20]

Answer:

0.5M is the answer.

Explanation:

1M solution is the solution containing 1mole solute dissolved per litre of solution.

Using unitary method,

1000cc gives 1M.

1cc gives 1/1000M.

500 cc gives 500/1000M=0.5M

7 0
3 years ago
PLEASE HELP!!! NEED TO PASS THIS TO THE FIRST SEMESTER!
Cloud [144]

Answer:

Reaction 1 is balanced but 2 is not balanced , the balance equation are :

1. CH_{3}COOH(aq) + NaHCO_{3}(aq)\rightarrow CO_{2}(g) + H_{2}O(l) + CH_{3}COONa(aq)

2.CaCl_{2}(aq) + 2NaHCO_{3}(aq)\rightarrow CaCO_{3}(aq) + H_{2}O(l) + 2NaCl(aq) + H_{2}O(aq)

Explanation:

Balanced Equations : These are the equation which follows the law of conservation of mass .

The total number of atoms present in reactant is equal to total number of atoms present in product.

1. CH_{3}COOH(aq) + NaHCO_{3}(aq)\rightarrow CO_{2}(g) + H_{2}O(l) + CH_{3}COONa(aq)

This is acid - base type reaction where

CH_{3}COOH(aq) act as Acid

NaHCO_{3}(aq) act as weak base

Reactant :CH_{3}COOH(aq) ,NaHCO_{3}

Number of atoms of :

C = 2 (CH_{3}COOH(aq)) + 1 (NaHCO_{3})

   = 2 + 1

   = 3

H  = 4(CH_{3}COOH(aq)) + 1 (NaHCO_{3})

     = 4 + 1

       5

O = 2(CH_{3}COOH(aq)) + 3 (NaHCO_{3})

    = 5

Na = 1 (NaHCO_{3})

     = 1

Product :  CO_{2}(g),H_{2}O(l) , CH_{3}COONa(aq)

Number of atoms :

C = 1(CO_{2}(g)) + 2(CH_{3}COONa(aq))

   = 1 + 2

   = 3

H = 2(H_{2}O(l)) + 3(CH_{3}COONa(aq))

   = 2 + 3

   = 5

O = 1(H_{2}O(l)) + 2(CH_{3}COONa(aq))

        +2(CO_{2}(g)

    = 1 + 2 + 2

    = 5

Na = 1(CH_{3}COONa(aq)

     = 1

Number of Na =1 , C = 3 , H= 5 and O =5 in both reactant and product , so it is a balanced reaction

2.CaCl_{2}(aq) + 2NaHCO_{3}(aq)\rightarrow CaCO_{3}(aq) + H_{2}O(l) + 2NaCl(aq) + CO_{2}(g)

This is double displacement reaction .

Check the balancing in both reactant and products should be :

Na = 2

H = 2

Ca = 1

C = 2

O = 6

Cl = 2

7 0
3 years ago
When multiplying numbers in scientific notation what do you do with exponents?
Basile [38]

Answer:

Subtract them.

Explanation:

''''"Since all number in scientific notation have base 10, we can always multiply them and divide them. To multiply two numbers in scientific notation, multiply their coefficients and add their exponents. To divide two numbers in scientific notation, divide their coefficients and subtract their exponents."""""

I was actually learned about this in school just found an source.

6 0
3 years ago
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