Answer:
0.25 mol/L
Explanation:
The following data were obtained from the question:
Initial volume (V1) = 4L
Initial concentration (C1) = 0.5 mol/L
Final volume (V2) = 4 + 4 = 8L
Final concentration (C2) =?
Applying the dilution formula, we can easily find the concentration of the diluted solution as follow:
C1V1 = C2V2
0.5 x 4 = C2 x 8
Divide both side by 8
C2 = (0.5 x 4 )/ 8
C2 = 0.25 mol/L
Therefore the concentration of the diluted solution is 0.25 mol/L
Answer: 899 g
Explanation:
Since the mass of a mole of diatomic chlorine is about 70.9 g/mol, this means that 875 grams is about 875/70.9 = 12.3 mol.
Hence, we know that chlorine is the limiting reactant, and that about 12.3 moles of chlorine will be consumed.
This means that 12.3(2)=24.6 grams of HCl will be produced, which will have a mass of about (24.6)(36.46)=899 g
General 'rule' - "like dissolves like". The solubility
of a solute in a solvent (that is, the extent of the mixing of the
solute and solvent species) depends on a balance between the natural
tendency for the solute and solvent species to mix and the tendency for a
system to have the lowest energy possible.
Hope this helps :p
The Boyle-Mariotte's law or Boyle's law is one of the laws of gases that <u>relates the volume (V) and pressure (P) of a certain amount of gas maintained at constant temperature</u>, as follows:
PV = k
where k is a constant.
We can relate the state of a gas at a specific pressure and volume to another state in which the same gas is at different P and V since the product of both variables is equal to a constant, according to the Boyle's law, which will be the same regardless of the state of the gas. In this way,
P₁V₁ = P₂V₂
Where P₁ and V₁ is the pressure and volume of the gas to a state 1 and P₂ and V₂ is the pressure and volume of the same gas in a state 2.
In this case, in the state 1 the gas occupies a volume V₁ = 100 mL at a pressure of P₁ = 150 kPa. Then, in the state 2 the gas occupies a volume V₂ (that we must calculate through the boyle's law) at a pressure of P₂ = 200 kPa. Substituting these values in the previous equation and clearing V₂, we have,
P₁V₁ = P₂V₂ → V₂ = 
→ V₂ = 
→ V₂ = 75 mL
Then, the volume occupied by the gas at 200 kPa is V₂ = 75 mL
Answer: This is called moles
Explanation: This is described to be the number of molecules, atoms or ions in a substance :)
