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Kobotan [32]
3 years ago
15

Solve the equation: −2(3x − 11) = 6(x + 4) − 38

Mathematics
1 answer:
vovangra [49]3 years ago
6 0
D.X=23 hope it help
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Part of the population of 5,750 elk at a wildlife preserve is infected with a parasite. A random sample of 50 elk shows that 2 o
Marta_Voda [28]

Answer:

230

Step-by-step explanation:

\frac{2}{50}=\frac{x}{5750}

cross multiply->11500=50x

divide both sides by 50 to isolate the variable

230=x

8 0
3 years ago
Please help me I will give you the brain thing and extra points. (image below) 3/4
Troyanec [42]
First, we have to find the difference between the x and y numbers in the table. By dividing the y by the x, the c is being multiplied by 15.

So the answer would be y=15x

Brainliest please!
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3 years ago
HELP ME WITH THIS . IF correct will get an brainliest<br> HURRRY
tekilochka [14]

X = 1

Explanation :

when you multiply negative 2 by negative six you get twelve. when you multiply positive one by negative six you get negative six.

7 0
2 years ago
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A company receives shipments of a component used in the manufacture of a component for a high-end acoustic speaker system. When
Tanya [424]

Answer:

ME= 2.33*\sqrt{\frac{0.096*(1-0.096)}{250}}= 0.0434

Step-by-step explanation:

For this case we have a sample size of n = 250 units and in this sample they found that 24 units failed one or more of the tests.

We are interested in the proportion of units that fail to meet the company's specifications, and we can estimate this with:

\hat p = \frac{24}{250}= 0.096

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

The confidence interval for a proportion is given by this formula  

\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}  

For the 98% confidence interval the value of \alpha=1-0.98=0.02 and \alpha/2=0.01, with that value we can find the quantile required for the interval in the normal standard distribution.  

z_{\alpha/2}=2.33  

And the margin of error would be:

ME= 2.33*\sqrt{\frac{0.096*(1-0.096)}{250}}= 0.0434

4 0
3 years ago
Solve: 18^x^2+4x+4=18^9x+18
Zina [86]

Answer:

Answer: x = –2 and x = 7

Step-by-step explanation:

5 0
3 years ago
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