
The tangential line at a certain point is just the derivative so.

. At the point (1,6) we plug the x value in and get the slope at the point (y ' = 2)
The tangential line at that point is
y - 6 = 2(x - 1) (this is the answer)
15p^2q^2 because you multiply the coefficients and the vaiables. 3x5 is 15, pxp is p^2, and qxq is q^2
Answer:
B. 81 weeks
Step-by-step explanation:
If we plug everything into the equation it should look like this:

Then we would subtract 1 from both sides, then we are left with <em>w:</em>
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<em>Hope this helps!</em>