1. The value of T is always greater then 1 or equal to 1. bez (n-6)^2 is always a whole no.
I think it's 0.385. I might be wrong. Try using WolframAlpha for this stuff, it should work.
1. 343x³ - 8 = 0
343x³ + 98x² - 98x² + 28x - 28x - 8 = 0
343x³ + 98x² + 28x - 98x² - 28x - 8 = 0
7x(49x²) + 7x(14x) + 7x(4) - 2(49x²) - 2(14x) - 2(4) = 0
7x(49x² + 14x + 4) - 2(49x² + 14x + 4) = 0
(7x - 2)(49x² + 14x + 4) = 0
7x - 2 = 0 or 49x² + 14x + 4 = 0
+ 2 + 2 x = -(14) ± √((14)² - 4(49)(4))
7x = 2 2(49)
7 7 x = -14 ± √(196 - 784)
x = ²/₇ 98
x = -14 ± √(-588)
-98
x = -14 ± 14i√(3)
-98
x = -14 + 14i√(3) or x = -14 - 14i√(3)
-98 -98
x = ¹/₇ - ¹/₇i√(3) or x = ¹/₇ + ¹/₇√(3)
x = ¹/₇ ± ¹/₇i√(3)
Solution Set: {¹/₇ ± ¹/₇i√(3), ²/₇}
2. 64x³ = 0
64 64
x³ = 0
∛(x³) = ∛(0)
x = 0
Solution Set: {0}
Answer:
Not a function.
Step-by-step explanation:
The definition of a function specifies that no value of <em>x</em> can be paired with two or more different values of <em>y</em>.
In the given relation: {(6, 2), (8, 2), (6, 3), (12, 3)},
The input value of x = 6 has two corresponding output values (y-coordinates): 2 and 3.
Therefore, the given relation is not a function.
