What is the percent of 33 of 28

2 answers:

5 0

It should end up like this 28/x=100/38
Next, cross multiply.
28 x 38= ? (answer)
100 times x= 100x
ans. divded by 100x

solve for x.
Hope this helps.

~Bob Ross ®

Ivan4 years ago

3 0

If you would like to know how much is 33 percent of 28, you can calculate this using the following steps:

33 percent of 28 = 33% * 28 = 33/100 * 28 = 231/25 = 9.24

Result: 33 percent of 28 is 9.24.

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The amounts of time that customers stay in a certain restaurant for lunch is normally distributed with a standard deviation of 1

hammer [34]

Answer:

99% CI: [45.60; 58.00]min

Step-by-step explanation:

Hello!

Your study variable is:

X: Time a customer stays in a certain restaurant. (min)

X~N(μ; σ²)

The population standard distribution is σ= 17 min

Sample n= 50

Sample mean X[bar]= 51.8 min

Sample standard deviation S= 27.68

You are asked to construct a 99% Confidence Interval. Since the variable has a normal distribution and the population variance is known, the statistic to use is the standard normal Z. The formula to construct the interval is:

X[bar] ± $Z_{1-\alpha /2}$ *(σ/√n)

$Z_{1-\alpha /2} = Z_{0.995}= 2.58$

Upper level: 51.8 - 2.58*(17/√50) = 45.5972 ≅ 45.60 min

Lower level: 51.8 + 2.58*(17/√50) = 58.0027 ≅58.00 min

With a confidence level of 99%, you'd expect that the interval [45.60; 58.00]min will contain the true value of the average time customers spend in a certain restaurant.

I hope you have a SUPER day!

PS: Missing Data in the attached files.