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emmasim [6.3K]
2 years ago
11

Carbohydrates are formed by plants converting water a d carbon dioxide into glucose and oxygen, in the photocatalyzed process is

called?
Chemistry
1 answer:
Dmitry [639]2 years ago
3 0
Photosynthesis maybe.
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Nitrogen dioxide is a red-brown gas that is responsible for the color of photochemical smog. What is the volume of 1 mol of nitr
Ray Of Light [21]
B ideal gas has a volume of 22.4
5 0
3 years ago
A single atom of an element has 21 nutrons 20 electtons and 20 protons which element is it
guajiro [1.7K]

your element would be calcium


7 0
3 years ago
Identify the Bronsted-Lowry acid, the Bronsted-Lowry base, the conjugate acid and the conjugate base for each of the following r
Vlad1618 [11]

Answer:

Acids → H₂CO₃ from equilibrium 1 and water, from equilibrium 2.

Bases → Water from equilibrium 1 and ammonia from equilibrium 2.

In 1st equilibrium, H₃O⁺ is the conjugate acid and HCO₃⁻ the conjugate base.

In 2nd equilibrium, NH₄⁺ is the conjugate acid, and OH⁻, the conjugate base.

Explanation:

By the Bronsted-Lowry you know that acids are the one that release protons and base are the ones that catch them.

For the first equilibrium:

H₂CO₃(aq) + H₂O(l) ⇄ H₃O⁺(aq) + HCO₃⁻(aq)

Carbonic acid is the acid → It donates the proton to water, so the water becomes the base. As H₂CO₃ is the acid,  the bicarbonate is the conjugate base (it can accept the proton from water to become carbonic acid, again) and the hydronium is the conjugate acid (it would release the proton to become water).

For the second equilibrium:

NH₃(aq) + H₂O(l) ⇄  NH₄⁺ (aq) + OH⁻(aq)

This is the opposite situation → Water relase the proton to ammonia, that's why water is the acid and NH₃, the base (it accepted to become ammonium). The NH₄⁺ is the conjugate acid (it can release the H⁺ to become ammonia) and the OH⁻ is the conjugate base (It can accept the proton to become water, again).  

5 0
3 years ago
Will you obtain a pure solid in evaporation technique? Justify your answer
aniked [119]

Evaporation technique is used to separate a compound dissolved in a solvent by vaporizing the solvent and converting it to gaseous state. This leaves behind the solid residue present in the solution after the pure solvent is vaporized. The solvent vapors can be collected and condensed to get pure solvent. But the solid residue cannot be considered pure as it is the left over solid after all the solvent is evaporated. If the solution has some impurities, the solid left over includes all of the impurities. So, we cannot obtain a pure solid in evaporation technique.

3 0
3 years ago
The activation energy for a reaction is changed from 184 kJ/mol to 60.5 kJ/mol at 600. K by the introduction of a catalyst. If t
Ahat [919]

Answer:

The catalyzed reaction will take 1,41 s

Explanation:

The rate constant for a reaction is:

k = A e^{-\frac{Ea}{RT}}

Assuming frequency factor is the same for both reactions (with and without catalyst) it is possible to obtain:

{\frac{k1}{k2}} = e^{-\frac{Ea_{2}-Ea_{1}}{RT}}

Replacing:

{\frac{k1}{k2}} = e^{-\frac{60,5kJ/mol-184kJ/mol}{8,314472x10^{-3}kJ/molK*600k}}

{\frac{k1}{k2}} = 5,64x10^{10}

That means the reaction occurs 5,64x10¹⁰ faster than the uncatalyzed reaction, that is 2537 years / 5,64x10¹⁰ = 4,50x10⁻⁸ years. In seconds:

4,50x10⁻⁸ years×\frac{365days}{1year}×\frac{24hours}{1day}×\frac{3600s}{1hour} =<em> 1,41 s</em>

I hope it helps!

6 0
3 years ago
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