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Svet_ta [14]
3 years ago
13

A flask of fixed volume contains 1.0 mole of gaseous carbon dioxide and 88 g of solid carbon dioxide. The original pressure and

temperature in the flask is 1.0 atm and 300. K. All of the solid carbon dioxide sublimes. The final pressure in the flask is 2.5 atm. What is the final temperature?
Chemistry
1 answer:
sweet [91]3 years ago
4 0

Answer:

the final temperature is 250 K

Explanation:

The computation of the final temperature is as follows:

PV = nRT

V1 = n1RT1 ÷ P1

And,

V2 = n2RT2 ÷ P2

n1T1 ÷ P1 = n2T2 ÷ P2

(1  × 300) ÷ 1 = (3 × T2) ÷ 2.5

T2 = (1 × 300 × 2.5) ÷ (1 × 3)

= 250 K

hence, the final temperature is 250 K

We simply applied the above formula so that the correct value could come

And, the same is to be considered

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A sample of gas contains 0.1800 mol of CO(g) and 0.1800 mol of NO(g) and occupies a volume of 23.2 L. The following reaction tak
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Explanation:

The reaction that occurs requires the same amount of CO and NO. As the moles added of both reactants are the same you don't have any limiting reactant. The only thing we need is the reaction where 4 moles of gases (2mol CO + 2mol NO) produce 3 moles of gases (2mol CO2 + 1mol N2). The moles produced are:

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