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vlada-n [284]
3 years ago
10

The mass of Carbon is 12 g/mol and the mass of oxygen is 16 g/mol. What is the approximate percent composition by mass of CO2 (f

ormula mass = 44)?
20% carbon and 80% oxygen
23% carbon and 77% oxygen
25% carbon and 75% oxygen
27% carbon and 73% oxygen
Chemistry
1 answer:
nikitadnepr [17]3 years ago
5 0

Answer:

the last one

27% by 73%

Explanation:

12/44*100 for C

and

16/44*100 for O

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Draw an alkyl bromide with proper stereochemistry that can be used to synthesize the given alkene as the exclusive product via a
enot [183]

Answer:

See explanation below

Explanation:

You forgot to put the picture to do so. In this case, I manage to find one, and I hope is the one you are looking for. If not, then post it again and I'll gladly help you out again.

According to the picture with the answer, we have a cyclohexane with 4 methyl groups there. Two of them are facing towards the molecule with a darker bond. This means that the alkyl bromide, should have a bromine in one of the bonds, and in order to produce an E2 reaction, this bromine should be facing in the opposite direction of the methyl groups which are facing towards. This is because an E2 reaction occurs with the less steric hindrance in the molecule. If the bromine is in the same direction as the methyl group, it will cause a lot more of work to do a reaction, and therefore, an E2 reaction. I will promote instead a E1 or a sustitution product.

Therefore the alkyl bromide should be like the one in the picture 2.

3 0
3 years ago
The size (radius) of an oxygen molecule is about 2.0 ×10−10m. Make a rough estimate of the pressure at which the finite volume o
belka [17]

Answer:

Explanation:

We can calculate the volume  of the oxygen molecule as the radius of oxygen molecule is given as 2×10⁻¹⁰m.

We know that volume=4/3×πr³

volume =4/3×π(2.0×10⁻¹⁰m)³

volume=33.40×10⁻³⁰m³

Volume of oxygen molecule=33.40×10⁻³⁰m³

we know the ideal gas equation as:

PV=nRT

k=R/Na

R=k×Na

PV=n×k×Na×T

n×Na=N

PV=Nkt

p is pressure of gas

v is volume  of gas

T is temperature of gas

N is numbetr of molecules

Na is avagadros number

k is boltzmann constant =1.38×10⁻²³J/K

R is real gas constant

So to calculate pressure using the  formula;

PV=NkT

P=NkT/V

Since there is only one molecule of oxygen so N=1

P=[1×1.38×10⁻²³J/K×300]/[33.40×10⁻³⁰m³

p=12.39×10⁷Pascal

8 0
3 years ago
A molecule made of hydrogen and carbon with Mr of 56 has the following composition: carbon 85.7%; hydrogen 14.3%. Calculate the
Veseljchak [2.6K]

Answer:

Assume that 100 grams of C2H4 is present. This means that there are 85.7 grams of carbon and 14.3 grams of hydrogen.

Convert these weights to moles of each element:

85.7 grams carbon/12 grams per mole = 7 moles of carbon.

14.3 grams hydrogen/1 gram per mole = 14 moles of hydrogen.

Divide by the lowest number of moles to obtain one mole of carbon and two moles of hydrogen.

Since we know that there cannot be a stable CH2 molecule, multiply by two and you have C2H4 which is ethylene - a known molecule.

The secret is to convert the percentages to moles and find the ration of the constituents.

5 0
2 years ago
Calculate the frequency
Ber [7]
Given: wavelength of Nitrogen laser (∧) = 337.1 nm = 337.1 X 10^-9 m

We know that, Energy of photon (E) = hc/∧ = hv
where, v = frequency of photon and c = speed of light = 3 X 10^8 m/s

Thus, v = c/∧ = (3 X 10^8)/ (337.1 X 10^-9) = 8.899 X 10^14 s-1.

Answer: F<span>requency of nitrogen laser = </span>8.899 X 10^14 s-1.
3 0
3 years ago
Read 2 more answers
What is the mass of an element with 15 protons, 13 electrons, and 11 neutrons? *
RSB [31]

Answer:

The mass of the element is 26.20 amu

Explanation:

In this question, we are asked to calculate the mass of an element with 15 protons, 13 electrons and 11 neutrons

To calculate the atomic mass of the element, we take into consideration the masses of the individual sub atomic particles

Electrons have 0 atomic mass unit(their masses are negligible) we have no business here, Protons have a mass of

1.00727647 amu, while the mass of neutron is 1.0086654 amu

The mass of 15 protons is thus 15 * 1.00727647 = 15.10914705 amu

The mass of 11 neutrons is 11 * 1.0086654 =

11.0953194 amu

Adding this together, we have ; 11.0953194 + 15.10914705 = approximately 26.20 amu

6 0
3 years ago
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