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vlada-n [284]
2 years ago
10

The mass of Carbon is 12 g/mol and the mass of oxygen is 16 g/mol. What is the approximate percent composition by mass of CO2 (f

ormula mass = 44)?
20% carbon and 80% oxygen
23% carbon and 77% oxygen
25% carbon and 75% oxygen
27% carbon and 73% oxygen
Chemistry
1 answer:
nikitadnepr [17]2 years ago
5 0

Answer:

the last one

27% by 73%

Explanation:

12/44*100 for C

and

16/44*100 for O

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What does AuCl, Gold (I) Chloride, decompose into?
Alexxx [7]

Answer:

Gold

Explanation:

Gold(I) chloride is a compound of gold and chlorine with the chemical formula AuCl

6 0
3 years ago
A metallurgist has one alloy containing 21% aluminum and another containing 42% aluminum. how many pounds of each alloy must he
Naily [24]
Answer is: 7.8 lb of 21% aluminum and 33.2 ib of <span>42% aluminum.</span>

ω₁<span> = 21% ÷ 100% = 0.21.
ω</span>₂<span> = 42% ÷ 100% = 0.42.
ω</span>₃<span> = 38% ÷ 100% = 0.38.
</span>m₁ = ?.

m₂<span> = ?.
</span>m₃ = m₁ + m₂<span>.
</span>m₃ = 41 pounds.

m₁ = 41 lb - m₂<span>.
ω</span>₁ · m₁ + ω₂ ·m₂ = ω₃ · m₃.

0.21 · (41 lb - m₂) + 0.42 · m₂ = 0.38 · 41 lb.

8.61 lb - 0.21m₂ + 0.42m₂ = 15.58 lb.

0.21m₂ = 6.97 lb.

m₂ = 6.97 lb ÷ 0.21.

m₂ = 33.2 lb.

m₁ = 41 lb - 33.2 lb.

m₁<span> = 7.8 lb.</span>



8 0
2 years ago
1. Identify the reactants in this chemical equation:<br> 2H2 + O2 + 2H2O
USPshnik [31]
Oxygen and hydrogen
6 0
3 years ago
Determine the mass of a gold bar that has a density of 19.3 g/cm3 and is 4.72 cm high by 8.21 cm long by 3.98 cm deep.
TEA [102]
The density of the gold is 19.3 grams/cc so each cc weighs 19.3grams. Now we can obtain the volume of gold from the given dimensions ie 4.72x8.21x3.98= 154.23 cc. So for the answer, just multiply the volume or 154.23 x 19.3= 2976.6 grams is the answer.
5 0
3 years ago
What is the name of the hydrocarbon CH3(CH2)6CH3?
Brums [2.3K]

Answer is: n-octane.

Octane is the straight-chain alkane (an acyclic saturated hydrocarbon) with eight carbon atoms.

Carbons in octane have sp3 hybridization (carbon’s 2s and three 2p orbitals combine into four identical sp3 orbitals).

Orbitals in sp3 hybridization have a tetrahedral arrangement and form single (sigma) bonds.

Burning octane fuel is very fast chemical reaction, it happens in immediately.

Main products of the combustion of fossil fuels are carbon(IV) oxide and water.  

Chemical reaction: C₈H₁₈ + 25/2O₂ → 8CO₂ + 9H₂O; ΔH = -5500 kJ/mol.


5 0
3 years ago
Read 2 more answers
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